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kaheart [24]
3 years ago
8

How do you say 2^3. 2 is squared, but what is the term for 3?

Mathematics
1 answer:
adell [148]3 years ago
5 0
Cubed.
or "to the power of" for 3 and higher powers.
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Which of the following pairs of lines are perpendicular? Select all that apply
ad-work [718]
Perpendicular lines will have negative reciprocal slopes

B. y = -4x+ 5  and y = 1/4x + 4
D. y = x + 4 and y = -x + 4
E. y = -3 and x = -3

4 0
3 years ago
Math grades assignment unit test part 2 adding and subtracting rational numbers?
Katena32 [7]

Answer: When we add or subtract rational numbers that have the same denominator, we add or subtract only the numerators. The denominators stay the same. When we add or subtract rational numbers with unlike denominators, we need to change the rational numbers to equivalent rational numbers that have the same denominators, before we find the sum or difference. Adding & Subtraction Rational Numbers

Step-by-step explanation:

3 0
3 years ago
Find the volume of these rctangular prisms length=6.4mm width=2.5mm hight=7mm<br> step by step pls
Soloha48 [4]

Answer:

The volume of this rectangular prism is 112mm.

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4 0
2 years ago
Determine the standard form of the equation for the circle with center (h,k) = (-5 ½) and radius r =1
wariber [46]
Asuuing yo meant (h,k)=(-5,1/2)

equation is (x-h)^2+(y-k)^2=r^2
(h,k) is center and r=radious
given that (h,k)=(-5,1/2) and r=1
h=-5
k=1/2

(x-(-5))^2+(y- \frac{1}{2} )^2=1^2
(x+5)^2+(y- \frac{1}{2} )^2=1
if you wanted us to expand
x²+y^2+10x-y+25.25=1
8 0
3 years ago
Perform the indicated operation. Be sure the answer is reduced.
avanturin [10]
<h3>Given Equation:-</h3>

\boxed{ \rm  \frac{4x^{2}y^{3}z}{9} \times  \frac{45y}{8 {x}^{5} {z}^{5} }}

<h3>Step by step expansion:</h3>

\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times  \dfrac{45y}{8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times  \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times  \dfrac{45y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times  \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y \times  {y}^{3} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y {}^{0}  \times  {y}^{3 + 1} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5 \times  {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \bf  \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}

8 0
2 years ago
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