Construct a truth table for proposition (¬p)\rightarrowq
1 answer:
Answer:
![\left[\begin{array}{ccc}(-p)&--->&q\\f&t&t\\f&t&t\\t&t&f\\t&f&f\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28-p%29%26---%3E%26q%5C%5Cf%26t%26t%5C%5Cf%26t%26t%5C%5Ct%26t%26f%5C%5Ct%26f%26f%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
First, we find all the possibilities for p and q in a table:
p q
t t
t f
f t
f f
then -p:
-p q
f t
f f
t t
t f
and we apply the operator --> (rightarrow), that is only f (false) y if the first one is t (true) and the second one is f (false)
-p ---> q
f t t
f t f
t t t
t f f
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