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geniusboy [140]
3 years ago
5

Which expression is equivalent to the following complex fraction? X/x-3/x^2/x^2-9

Mathematics
2 answers:
Likurg_2 [28]3 years ago
6 0

Answer:

c

Step-by-step explanation:

rewona [7]3 years ago
3 0

Answer:

C) \frac{x+3}{x}

Step-by-step explanation:

The given expression is

\frac{\frac{x}{x-3} }{\frac{x^2}{x^2-9} }

We rewrite to obtain:

\frac{x}{x-3} \div \frac{x^2}{x^2-9}

Multiply the first fraction by the reciprocal of the second to get;

\frac{x}{x-3} \times \frac{x^2-9}{x^2}

Factor the numerator using difference two squares;

\frac{x}{x-3} \times \frac{x^2-3^2}{x^2}

\frac{x}{x-3} \times \frac{(x-3)(x+3)}{x^2}

Cancel out the common factors to get;

\frac{1}{1} \times \frac{(1)(x+3)}{x}

This simplifies to;

\frac{x+3}{x}

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Answer:

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Aliun [14]
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-----------------------------------

Work Shown:

20k+50 = 10*2k + 10*5
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