Answer:
Vamos a inventa tres multiplicaciones de seis factores en la que el resultado sea positivo, es decir un número mayor que cero, en la otra negativo, es decir, un número menor que cero y por último otra multiplicación que de como resultado el cero "0".
Primero recordemos que:
Los factores son los números que se multiplican.
Seis factores serían 6 números.
Multiplicación con resultado positivo, es decir mayor a 0:
2×3×4×2×1×5=240
Multiplicación con resultado negativo, es decir menor a 0:
-4×2×5×2×1×10= -400
Multiplicación con resultado cero:
2×4×6×7×11×0=0
Step-by-step explanation:
Brainliest please
8 and 1 are alternate exterior angles.
5x(6^2 +1)
Is 30x3+5x in factored form
125 > 50 + 4.25*p
subtract 50 from each side
75 =>4.25p
divide by 4.25
p>17.64
He may invite up to 17 people ( if he doesn't have to pay for himself)
He may invite 16 if he has to pay for himself
<span>A. y=secx
This problem deals with the various trig functions and is looking for those points where they are undefined. Since the only math operations involved is division, that will happen with the associated trig function attempts to divide by zero. So let's look at the functions that are a composite of sin and cos.
sin and cos are defined for all real numbers and range in value from -1 to 1.
sin is zero for all integral multiples of pi, and cos is zero for all integral multiples of pi plus pi over 2. So the functions that are undefined will be those that divide by cos.
tan = sin/cos, which will be undefined for x = π/2 ±nπ
cot = cos/sin, which will be undefined for x = ±nπ
sec = 1/cos, which will be undefined for x = π/2 ±nπ
csc = 1/sin, which will be undefined for x = ±nπ
Now let's look at the options and pick the correct one.
A. y=secx
* There's a division by cos, so this is the correct choice.
B. y=cosx
* cos is defined over the entire domain, so this is a bad choice.
C. y=1/sinx
* The division is by sin, not cos. So this is a bad choice.
D. y=cotx,
* The division is by sin, not cos. So this is a bad choice.</span>
