Question

(-1,3) (3,0) (-1.-2) find perimiter

Answer 1

Answer:

$p$≈$14.5$

Step-by-step explanation:

Find the distance between the three pairs first using the distance formula:

$\sqrt{(x2-x1)^2+(y2-y1)^2}$

Take the first two points, $(-1,3)(3,0)$ and insert the values:

$\sqrt{(3-(-1))^2+(0-3)^2}$

Simplify parentheses (two negatives makes a positive):

$\sqrt{(3+1)^2+(0-3)^2}\\\\ \sqrt{(4)^2+(-3)^2}\\\\\sqrt{16+9}\\ \\\sqrt{25}=5$

The distance between the first two points is 5. Use the nest two points, $(3,0)(-1,-2)$ and insert values:

$\sqrt{(-1-3)^2+(-2-0)^2}$

Simplify parentheses:

$\sqrt{(-4)^2+(-2)^2}\\ \\\sqrt{16+4} \\\\\sqrt{20}=4.5$

The distance between the nest two point is about 4.5. Use the remaining two points, $(-1,-2)(-1,3)$ and insert values:

$\sqrt{(-1-(-1))^2+(3-(-2))^2}$

Simplify parentheses (two negatives makes a positive):

$\sqrt{(-1+1)^2+(3+2)^2}\\\\\sqrt{(0)^2+(5)^2}\\ \\\sqrt{0+25}\\ \\\sqrt{25}=5$

The distance between the last points is 5. Add the distances together to find the perimeter of the triangle:

$5+4.5+5\\10+4.5\\14.5$

The perimeter is about 14.5.