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3 years ago

I honestly have no clue how to do these

Mathematics

1 answer:

densk [106]3 years ago

4 0

Answer:

$-2^{2} -4(1)(5)$

so the answer would be c.

Step-by-step explanation:

The discriminant is the following equation:

$b^{2} -4ac$

You just simply plug in the values of the coefficients.

$0=x^{2} -2x+5$

a = 1 (first terms coefficient)

b = -2 (second terms coefficient)

c = 5 (last terms coefficient)

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Lisa wrote the expression (3x + 6x) - 2(x + 1) + 5. She simplified the expression using the following steps:

Ivanshal [37]

Answer:

Step 1. Should be 3(x +2x) -2(x +1) +5 . . .

or . . . 3x(1 +2) -2(x +1) +5 . . .

or . . . 9x -2(x+1) +5

Step-by-step explanation:

Lisa apparently failed to realize that both terms inside the first set of parentheses have 3x as a factor. They are like terms, so could be combined directly. If Lisa really wants to factor out 3 or 3x, she could do so and then combine the remaining factors at another step.

6 0

3 years ago

Read 2 more answers

Another math question I need help with! please answer!

wariber [46]

The answer is c I hope that helps

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3 years ago

Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95

Virty [35]

Answer:

$L(x)=1+\dfrac{1}{3}x$

$\sqrt[3]{0.95} \approx 0.9833$

$\sqrt[3]{1.1} \approx 1.0333$

Step-by-step explanation:

Given the function: $g(x)=\sqrt[3]{1+x}$

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial, $L(x)=f(a)+f'(a)(x-a)$

a=0

$g(0)=\sqrt[3]{1+0}=1$

$g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}$

Therefore:

$L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x$

(b) $\sqrt[3]{0.95}= \sqrt[3]{1-0.05}$

When x = - 0.05

$L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833$

$\sqrt[3]{0.95} \approx 0.9833$

(c)

(b) $\sqrt[3]{1.1}= \sqrt[3]{1+0.1}$

When x = 0.1

$L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333$

$\sqrt[3]{1.1} \approx 1.0333$

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3 years ago

You have been asked to build a scale model of your school out of toothpicks. imagine your school is 30 feet tall. your scale is

sveticcg [70]

Since your scale is 1ft:1.26cm, a 30-ft tall school would need to have a $30*1.26=37.8$ cm model. Dividing this by how tall each toothpick is, you'll get:

$\frac{37.8}{6.3} =6$

ANSWER: The model would be 6 toothpicks tall.

To find out how many cotton swabs you'll need, we just divide 37.8 by how tall each swab is:

$\frac{37.8}{7.7} =5$

ANSWER: The model would be 5 cotton swabs tall.

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USPshnik [31]

The tree in exactly A.7.5 meters

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