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3 years ago

Draw the box and whisker plot for the data.

Mathematics

2 answers:

guajiro [1.7K]3 years ago

8 0

Answer:

gdghfdhfghfdthgfdtdfthtdfgh the third one

Step-by-step explanation:

Zarrin [17]3 years ago

5 0

The second option is the right one

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A sales man is paid a basic wage of $225 per week. In addition he is paid a commission of 3% on the value of goods he sells abov

mihalych1998 [28]

Answer:

Commission = $375

Total earnings = $600

Step-by-step explanation:

He gets 3% of any sale he makes above %5500 which means his commission received on this sale is;

= 3% * $12500

= $\frac{3}{100} *$ $12500

= 3* 125

= $375

This means his total earnings for the week will be the basic wage plus his commission

$225 + $375

= $600

3 0

3 years ago

Art [367]

Answer:

I got 1,800 hope this helps

6 0

2 years ago

Read 2 more answers

Determine the angle at the centre of a circle with radius 12.0 cm for an arc length of of 21.0 cm.

nata0808 [166]

Answer:

$\theta=\dfrac{7}{4}\ \text{radian}$

Step-by-step explanation:

We have,

Radius of the circle is 12 cm

Arc length, l = 21 cm

It is required to find the central angle of the circle. The formula for the length of an arc of a circle is :

$l=r\times \theta$

$\theta$ is central angle

$\theta=\dfrac{l}{r}\\\\\theta=\dfrac{21}{12}\\\\\theta=\dfrac{7}{4}\ \text{radian}$

So, the angle at the centre of the circle is $\dfrac{7}{4}\ \text{radian}$ .

7 0

2 years ago

The square root of 9x plus 7 plus the square rot of 2x equall to 7

Oliga [24]

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
x=2

4 0

3 years ago

16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.

Katyanochek1 [597]

We will use the sine and cosine of the sum of two angles, the sine and consine of $\frac{\pi}{2}$ , and the relation of the tangent with the sine and cosine:

$\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta$

$\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0$

$\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}$

If you use those identities, for $\alpha=x,\ \beta=\dfrac{\pi}{2}$ , you get:

$\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x$

$\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x$

Hence:

$\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x$

3 0

3 years ago