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insens350 [35]
3 years ago
10

a room's floor has a width tht is 5 meters shorter than its length. if the perimeter of the floor is 4y+1 meters, can u solve fo

r its length? Explain y and show ur work.
Mathematics
1 answer:
ira [324]3 years ago
6 0

Answer: No, we cannot find for its length as we can see that variables got cancelled so, we are not able to find any value for 'y'.

Step-by-step explanation:

Since we have given that

Let length of room's floor be y

Let width of a room's floor be y-5

Perimeter of room's floor be 4y+1

As we know the formula for " Perimeter of rectangle ":

Perimeter=2(Length+Width)\\\\Perimeter=2(y+y-5)\\\\4y-1=2(2y-5)\\\\4y-1=4y-20\\\\4y-4y=-20+1\\\\0\neq -19

No, we cannot find for its length as we can see that variables got cancelled so, we are not able to find any value for 'y'.


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Step-by-step explanation:

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Step 2: Subtract 7 on both sides

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Approximate 17.850 litres to the nearest 1/2 litre
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En un acuario compraron 30 peces y 18 tortugas de agua. Los van a colocar en peceras. Cada una tiene que haber la misma cantidad
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Answer:

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3 peces por tanque

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Step-by-step explanation:

Resolvemos la pregunta anterior utilizando el cálculo de múltiplo común más bajo

En un acuario compraron 30 peces y 18 tortugas de agua.

Encuentre y enumere los múltiplos de cada número hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

El mínimo común múltiplo es el número de tanques

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18, 36, 54, 72, 90, 108, 126

Múltiplos de 30:

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b) ¿Cuántos peces y tortugas puede tener cada tanque?

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= 3 peces por tanque

El número de tortugas de agua que puede tener cada tanque =

Número de tanques / Número de tortugas de agua

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5 0
3 years ago
Hi :) this lesson is about 30-60-90 triangles.
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3 years ago
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