Question

Three numbers have a sum of 68. The second number is 1 less than twice the first. The third number is three times the second. What are the three numbers?

Answer 1

Answer:

First number: 71/7

Second number: 135/7

Third number: 270/7

Step-by-step explanation:

First number = x

Second number= 2x-1

Third number= 2(2x-1)

x+(2x-1)+2(2x-1)= 68

3x-1+4x-2=68

7x-3=68

7x=71

x=71/7

You can check by plugging in the x into the equation.