Three numbers have a sum of 68. The second number is 1 less than twice the first. The third number is three times the second. Wh
at are the three numbers?
1 answer:
Answer:
First number: 71/7
Second number: 135/7
Third number: 270/7
Step-by-step explanation:
First number = x
Second number= 2x-1
Third number= 2(2x-1)
x+(2x-1)+2(2x-1)= 68
3x-1+4x-2=68
7x-3=68
7x=71
x=71/7
You can check by plugging in the x into the equation.
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