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Flauer [41]
3 years ago
10

Three numbers have a sum of 68. The second number is 1 less than twice the first. The third number is three times the second. Wh

at are the three numbers?
Mathematics
1 answer:
Vesnalui [34]3 years ago
4 0

Answer:

First number: 71/7

Second number: 135/7

Third number: 270/7

Step-by-step explanation:

First number = x

Second number= 2x-1

Third number= 2(2x-1)

x+(2x-1)+2(2x-1)= 68

3x-1+4x-2=68

7x-3=68

7x=71

x=71/7

You can check by plugging in the x into the equation.

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How do you reduce 2 1/32
loris [4]

Answer:

2\frac{1}{32}=\frac{2\cdot 32+1}{32}=\frac{65}{32}

Step-by-step explanation:

Considering the expression

2\frac{1}{32}

As

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fraction:}\:a\frac{b}{c}=\frac{a\cdot \:c+b}{c}

<em>Improper fraction is a fraction which has numerator greater than denominator, such as 5/3.</em>

So,

2\frac{1}{32}=\frac{2\cdot 32+1}{32}=\frac{65}{32}

As 2\frac{1}{32} is converted into improper fraction  \frac{65}{32} .

And  \frac{65}{32} can not be further reduced.

Therefore,

2\frac{1}{32}=\frac{2\cdot 32+1}{32}=\frac{65}{32}

Keywords: fraction, reduced form, improper fraction

Learn more about fractions from brainly.com/question/535608

#learnwithBrainly

7 0
3 years ago
Six times the amount of women that were at the banquet last year will be in attendance this year. The same amount of men will be
Rina8888 [55]

Answer:

m+6n

Step-by-step explanation:

Let number of men who attended last year=m

Let number of women who attended last year=n

This year, we expect Six times the amount of women attendance last year =6 X n = 6n

The same number of men, m will be expected this year

Therefore, Number of Expected Attendees

= Number of Men + (Six Times the Number of Women)

=m+6n

We can expect (m+6n) people to be in attendance this year.

5 0
3 years ago
When the sum of an unknown number and twenty two is divided by the unknown number, the quotient is 12. What is the unknown numbe
Gnom [1K]
You would basically work backwards and do inverse operations




12
24*
__
288



288/24= 12
8 0
3 years ago
What do a parallelogram and kite have in common?
grigory [225]
They both have 4 congruent sides and angles.
4 0
4 years ago
Consider the sequence 10, 2..
romanna [79]

Answer:  see below

<u>Step-by-step explanation:</u>

1) 10, 2, 1.2, 1.12, 1.112, 1.1112

t_n=\dfrac{t_{n-1}}{10}+1

t₁ = 10

t₂ = 10/10 + 1    = 2

t₃ = 2/10 + 1     = 1.2

t₄ = 1.2/10 + 1   = 1.12

t₅ = 1.12/10 + 1  = 1.112

t₆ = 1.112/10 + 1 = 1.1112

2)  10, 2, -2, -4, -5, -5.5, ...

t_n=\dfrac{t_{n-1}}{2}-3

t₁ = 10

t₂ = 10/2 - 3 =   2

t₃ = 2/2 - 3  =  -2

t₄ = -2/2 - 3 =  -4

t₅ = -4/2 - 3 =  -5

t₆ = -5/2 - 3 = -5.5

8 0
3 years ago
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