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sattari [20]
3 years ago
15

In a shipment of 850 widgets, 32 are found to be defective. At this rate, how many defective widgets could be expected in 22,000

widgets? Round to the nearest whole number.
Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
7 0
32/850 are defective
22000/850=25.88
25.88×32=828.23
round down to 828
out of 22,000 widgets 828 can be expected to he defective
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For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (2,7) and has a slope of 6?
Mumz [18]

Answer:

y= 6x - 5

Step-by-step explanation:

3 0
3 years ago
A fitness club has two options, one for members and one for nonmembers. Members pay a one-time registration fee of $12 plus $8 p
Liula [17]

Answer:

See below.

Step-by-step explanation:

Let's look at the cost for members (C1) first.  Let x be the number of visits.

C1(x) = 12 + 8x

For non-members (C2), we can do the same.

C2(x) = 10x

You can graph these two equations.

x        C1         C2

0       12          0

1        20        10

2       28        20

3       36        30

4       44        40

5       52        50

6       60        60

7       68        70

Let's make the two equations equal, to find out where the benefit is the same.

12 + 8x = 10x

2x = 12

x = 6

Up to 5 visits, the non-member cost is better.  At 6 visits, there's the same price.  For more than 6 visits, the member cost is better.

7 0
3 years ago
The side of cube is 3m 30cm long, find out its volume​
Anettt [7]
90 volume because 3 multiples by 30 = 90
7 0
3 years ago
G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =
laiz [17]

Given:

The two functions are:

g(b)=5b-9

h(b)=(b-1)^2

To find:

The value of (h\circ g)(-6).

Solution:

We have,

g(b)=5b-9

h(b)=(b-1)^2

We know that,

(h\circ g)(b)=h(g(b))

(h\circ g)(b)=h(5b-9)

(h\circ g)(b)=[(5b-9)-1]^2

(h\circ g)(b)=[5b-10]^2

Putting b=-6, we get

(h\circ g)(-6)=[5(-6)-10]^2

(h\circ g)(-6)=[-39-10]^2

(h\circ g)(-6)=[-49]^2

(h\circ g)(-6)=2401

Therefore, the value of (h\circ g)(-6) is 2401.

7 0
3 years ago
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