n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
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ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
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n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
Answer:
Should be 1 if im not wrong Then Mark Me brainliest
Step-by-step explanation:
a negative times a neg equals a posative
Neg x pos = neg
pos x neg = neg
pos x pos = pos
neg x neg = pos
so if there greater then over neg<, >,=
You would look at the problem for given f(x)=
x → -1 and neg times neg more or less
-1 x -1 = 1
Answer:
Step-by-step explanation:
1 yard = 3 feet
11 feet * (1 yard)/(3 feet) =11/3 yards = 3⅔ yards
Javon can cut three one-yard pieces. ⅔ yard is left over.
Answer:
greater than 1
Step-by-step explanation:
its greater because 1.01 is greater than 1
Hey!
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Solution:
We can get two different ways of 1:6 by add +1:+6.
1 + 1 = 6 + 6
2:12
2 + 1 = 12 + 6
3:18
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Answer:
2:12 and 3:18
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Hope This Helped! Good Luck!