It's given in the question,
P, Q, V and K are collinear.
VP = 14x + 4
PK = x + 630
VQ = 17x + 6
KQ = 11x + 5
By segment addition postulate,
KQ + VQ + VP = KP
Substitute the values in the expression,
(11x + 5) + (17x + 6) + (14x + 4) = x + 630
(11x + 17x + 14x) + (5 + 6 + 4) = x + 630
42x + 15 = x + 630
42x - x = 630 - 15
41x = 615
x = 
x = 15
Therefore, value of VP = (14x + 4)
= 14(15) + 4
= 214 units
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To figure out this problem you need to find the area of the cylinder A= pi r^2 *h
Then find the area of the cone 1/3*pi*r^2 *h
Subtract the two answers
Answer:
4^(11/20)
Step-by-step explanation:
The applicable rule of exponents is ...
(a^b)/(a^c) = a^(b-c)
Using that here, we have ...
4^(3/4)/4^(1/5) = 4^(3/4 -1/5)
= 4^(15/20 -4/20) = 4^(11/20)
Hey man, we’ll first of all you just need to substitute the value of a=4 and b=-1 into the equation and you’ll get your answer. Don’t worry I’ll show you an answer.
The answer should be 53/30 or 1 23/30
