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Dafna1 [17]
2 years ago
15

Can some help me for number 25 where it says Evaluate this simplified polynomial for a=4 and b =-1. I don't understand it correc

tly please help man ​

Mathematics
2 answers:
Valentin [98]2 years ago
8 0
Hey man, we’ll first of all you just need to substitute the value of a=4 and b=-1 into the equation and you’ll get your answer. Don’t worry I’ll show you an answer.

Crank2 years ago
4 0
I plugged in the values for a and b and got 11
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3^x=1/9<br><br> What does x equal?
Nastasia [14]

Answer: The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try!

Step-by-step explanation:

7 0
3 years ago
4y+2x=180 solve for x and y
kirill [66]
There you go!! Hope it helps

5 0
3 years ago
How do the values in Pascal’s triangle connect to the coefficients?
damaskus [11]

Explanation:

Each row in Pascal's triangle is a listing of the values of nCk = n!/(k!(n-k)!) for some fixed n and k in the range 0 to n. nCk is <em>the number of combinations of n things taken k at a time</em>.

If you consider what happens when you multiply out the product (a +b)^n, you can see where the coefficients nCk come from. For example, consider the cube ...

  (a +b)^3 = (a +b)(a +b)(a +b)

The highest-degree "a" term will be a^3, the result of multiplying together the first terms of each of the binomials.

The term a^b will have a coefficient that reflects the sum of all the ways you can get a^b by multiplying different combinations of the terms. Here they are ...

  • (a +_)(a +_)(_ +b) = a·a·b = a^2b
  • (a +_)(_ +b)(a +_) = a·b·a = a^2b
  • (_ +b)(a +_)(a +_) = b·a·a = a^2b

Adding these three products together gives 3a^2b, the second term of the expansion.

For this cubic, the third term of the expansion is the sum of the ways you can get ab^2. It is essentially what is shown above, but with "a" and "b" swapped. Hence, there are 3 combinations, and the total is 3ab^2.

Of course, there is only one way to get b^3.

So the expansion of the cube (a+b)^3 is ...

  (a +b)^3 = a^3 + 3a^2b +3ab^2 +b^3 . . . . . with coefficients 1, 3, 3, 1 matching the 4th row of Pascal's triangle.

__

In short, the values in Pascal's triangle are the values of the number of combinations of n things taken k at a time. The coefficients of a binomial expansion are also the number of combinations of n things taken k at a time. Each term of the expansion of (a+b)^n is of the form (nCk)·a^(n-k)·b^k for k =0 to n.

6 0
3 years ago
Hey can you please help me posted picture of question
SpyIntel [72]
We are to find the Probability the someone buys a book that is paperback and fiction.

Let P(F) represents the event that the book is fiction and P(P) represents the event that the book is paperback. We are to find P(F∩P)

P(F∩P) = P(F) x P(P)

From the tree diagram we can see that:

P(F) = 0.45
P(P) = 0.65

Using the values, we get:

P(F∩P) = 0.45 x 0.65 = 0.2925

So, the Probability the someone buys a book that is paperback and fiction is 0.2925.

So, option B gives the correct answer
3 0
3 years ago
11. Keng creates a painting on a rectangular canvas with a width that is four inches longer
GrogVix [38]

Part A

<h3>Answer:  h^2 + 4h</h3>

-------------------

Explanation:

We multiply the length and height to get the area

area = (length)*(height)

area = (h+4)*(h)

area = h(h+4)

area = h^2 + 4h .... apply the distributive property

The units for the area are in square inches.

===========================================================

Part B

<h3>Answer:  h^2 + 16h + 60</h3>

-------------------

Explanation:

If we add a 3 inch frame along the border, then we're adding two copies of 3 inches along the bottom side. The h+4 along the bottom updates to h+4+3+3 = h+10 along the bottom.

Similarly, along the vertical side we'd have the h go to h+3+3 = h+6

The old rectangle that was h by h+4 is now h+6 by h+10

Multiply these expressions to find the area

area = length*width

area = (h+6)(h+10)

area = x(h+10) ..... replace h+6 with x

area = xh + 10x .... distribute

area = h( x ) + 10( x )

area = h( h+6 ) + 10( h+6 ) .... plug in x = h+6

area = h^2+6h + 10h+60 .... distribute again twice more

area = h^2 + 16h + 60

You can also use the box method or the FOIL rule as alternative routes to find the area.

The units for the area are in square inches.

6 0
3 years ago
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