(a)Two charges are placed on the x-axis: one is placed at x = 3 m and the other is at x = -3 m. The magnitude of both charges is 2.3 µC but the blue one (at x = -3 m) is positive while the red one (at x = +3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(b) Now the positive and negative charge switch places. The magnitude of the charges is still 2.3 µC where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(c) Now both charges (still at x = -3 m and x = +3 m) are positive. The magnitude of both charges is still 2.3 µC.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(d) Finally, both charges (still at x = -3 m and x = +3 m) are negative. The magnitude of both charges is still 2.3 µC.
Step-by-step explanation:
Statement. Reason
→ 9(x-6)+41 = 75. Transposing the like terms.
→ 9(x-6) = 75 - 41 Performing subtraction of the term in RHS
→ 9(x-6) = 34 Performing multiplication in LHS.
→ 9x - 54 = 34 Distributive property
→ 9x = 34 + 54 Performing addition of the term in RHS.
→ 9x = 88. Now, transpose 9 from LHS to RHS , it's arthmetic operator will get changed.
→ x = 88/9
Answer: 5/2
Explanation:
According to 30-60-90 triangle rule:
The side opposite of 30 degree is equal to half of the hypotenuse and the hypotenuse here is 5 so therefore x = 5/2
Answer:8_1
Step-by-step explanation:
Answer:
Step-by-step explanation:
If ΔABC ~ ΔDEF
Then their sides must be proportional such that:
=> 
Cross Multiplying
=> x * 6 = 8*3
=> 6x = 24
Dividing both sides by 6
=> x = 4
