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3 years ago

Which ordered pair is a solution to the system of linear equations?

Mathematics

2 answers:

Oksanka [162]3 years ago

7 0

Answer:

(0,2) is your answer. Have a nice day!!!

masha68 [24]3 years ago

6 0

Answer:

0,2

Step-by-step explanation:

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NOTE: Angles not necessarily drawn to scale.

Anastasy [175]

The answer is 13!! :)

7 0

3 years ago

Read 2 more answers

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

3 0

3 years ago

The ratio of apples and oranges are 1:3 what would happen if I had 150 oranges

oksian1 [2.3K]

multiply the 3 by how ever much to get 150

there will be 50 apples

5 0

3 years ago

Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).

SVEN [57.7K]

Step-by-step explanation:

y-y₁=m(x-x₁)

1-(-4)=m(4-3)

5=m

5 0

3 years ago

3/7 of 8th graders play sports. is 3/5 of the 8th graders that play sports are boys, what fraction of the 8th graders are boys

Svetach [21]

Answer:

$\dfrac{9}{35}$ is the fraction of 8th graders who are boys.

Step-by-step explanation:

Let total number of 8th graders = $x$

Given that, $\frac{3}{7}$ of 8th graders play sports

$\Rightarrow$ 8th graders who play sports = $\frac{3}{7} \times x$

Also, Given that, $\frac{3}{5}$ of 8th graders that play sports are boys

Number of 8th graders that play sports, and are boys = $\frac{3}{5} \times \text{Number of 8th graders who play sports}$

$\Rightarrow \dfrac{3}{5} \times \dfrac{3}{7} \times x\\\Rightarrow \dfrac{9}{35} \times x$

Hence, the answer is:

$\dfrac{9}{35}$ is the fraction of 8th graders who are boys.

6 0

3 years ago