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Gnoma [55]
3 years ago
14

. Complete the missing steps in the paragraph proof of Theorem 3-8.

Mathematics
1 answer:
Crank3 years ago
8 0
To solve for the missing steps, let's rewrite first the problem.

Given:

In a plane, line m is perpendicular to line t or  m⟂t
                  line n is perpendicular to line t  or  n⟂t


Required:

Prove that line m and n are parallel lines


Solution:

We know that line t is the transversal of the lines m and n.

With reference to the figure above, 

∠ 2 and ∠ 6 are right angles by definition of <u>perpendicular lines</u>. This states that if two lines are perpendicular with each other, they intersect at right angles.

So ∠ 2 ≅ ∠ 6. Since <u>corresponding</u> angles are congruent. 

Therefore, line m and line n are parallel lines.
<span>
<em>ANSWERS: perpendicular lines, corresponding</em>

</span>
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Multiply<br> (x-6)(4x + 3)<br> A. 47-32-18<br> B. 4) - 24%-18<br> C. 47 - 21%-18<br> D. 4/2 - 18
PilotLPTM [1.2K]

Answer:

4x² - 21x - 18

Step-by-step explanation:

Use FOIL.

(x-6)(4x+3)\\\\x*4x = 4x^2\\\\x * 3 = 3x\\\\-6 * 4x= -24x\\\\-6 * 3 = -18\\\\\\4x^2+3x-24x-18\\\\\boxed{4x^2-21x-18}

Hope this helps.

5 0
2 years ago
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5x-2y=11 and 3x+4y=4<br>Find the value of x and y in equation.​
nadya68 [22]
  • 5x-3y=11---(1)
  • 3x+4y=4---(2)

(1)×3 and (2)×5

  • 15x-9y=33-(3)
  • 15x+20y=20-(4)

Subtract both

\\ \sf\longmapsto -29y=13

\\ \sf\longmapsto y=\dfrac{-13}{29}

  • Put in eq(1)

\\ \sf\longmapsto 5x+\dfrac{-117}{29}=11

\\ \sf\longmapsto 5x=11+\dfrac{117}{29}=\dfrac{261+117}{29}=\dfrac{278}{29}

\\ \sf\longmapsto x=\dfrac{278}{145}

7 0
2 years ago
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I'm having a hard time with this question so someone help please
bulgar [2K]

Answer:

  7.7 km

Step-by-step explanation:

This question is asking you to find the third side of a triangle in which two sides and an angle not between them are given. The law of sines provides the necessary relationships.

<h3>Law of Sines</h3>

The Law of Sines tells you that triangle side lengths are proportional to the sine of the opposite angle. For this triangle TPJ, the relation is ...

  t/sin(T) = p/sin(P) = j/sin(J)

We are given T=68°, p=5.2 km, t=7.5 km, and we are asked to find the length of j, the TP distance.

<h3>Setup</h3>

We know the sum of angles in a triangle is 180°, and the sine of an angle is equal to the sine of its supplement. This lets us fill in the Law of Sines equation like this:

  7.5/sin(68°) = 5.2/sin(P) = j/sin(68°+P) . . . . . solve for j

<h3>Solution</h3>

This can be solved in two steps. First, we find angle P, then we use that to find length j.

  sin(P) = 5.2/7.5 × sin(68°) ≈ 0.642847

  P = arcsin(0.642847) ≈ 40.0045°

Now, we can find j:

  j = 7.5 × sin(68° +40.0045°)/sin(68°) ≈ 7.693 . . . km

The distance from the tower to the plane is about 7.7 km.

__

<em>Additional comment</em>

We have used T, P, and J to refer to the vertices at the tower, plane, and jet.

The triangle can also be solved using the Law of Cosines. In that case, the missing side will be the solution to a quadratic equation with irrational coefficients.

3 0
2 years ago
A bag contains 3 purple and 5 orange jelly-beans. If one jelly-bean is selected and is NOT replaced and a second jelly-bean is s
Elan Coil [88]

P(orange and then a purple) is 15/56.

P(two purples in a row) is 6/56.

<u>Step-by-step explanation:</u>

  • A bag contains 3 purple and 5 orange jelly-beans.
  • The total jelly-beans in the bag = 3 purple + 5 orange = 8 jelly-beans.

<u>Without replacement, find P(orange and then a purple) :</u>

P (orange) = No.of orange jelly-beans / total jelly-beans.

⇒ 5 / 8

P (purple) = No.of purple jelly-beans / remaining jelly-beans from the total

⇒ 3 / 7

P(orange and then a purple) = P (orange) × P (purple)

⇒ 5/8 × 3/7

⇒ 15/56

<u>Without replacement, find P(two purples in a row) :</u>

P (1st purple) = No.of purple jelly-beans / total jelly-beans.

⇒ 3 / 8

P (2nd purple) = remaining no.of purple jelly-beans / remaining jelly-beans from the total.

⇒ 2 / 7

P(two purples in a row) = P (1st purple) × P (2nd purple)

⇒ 3/8 × 2/7

⇒ 6/56

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In the figure below, AD and BE are diameters of circle P. What is the arc measure of CD in degrees?
podryga [215]

Answer:

Dude, we need an image to know what the figure is.

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3 years ago
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