Question

Help please!!! Pre-calculus

Answer 1

Answer:

P ( 3, - pi/3 + 2 pi n) or P ( -3 , -pi/3 + pi(2 n +1))

Step-by-step explanation:

P ( 3, - pi/3)

We can circle 2pi n around the circle and be back at the same polar coordinate

P ( 3, - pi/3 + 2 pi n)

or we can flip the radius to a negative and add pi to the theta

P ( -3, - pi/3 + pi)

Then we can circle 2pi n around the circle and be back at the same polar coordinate

P ( -3 , -pi/3 + 2 pi n +pi)

P ( -3 , -pi/3 + pi(2 n +1))