Help please!!! Pre-calculus

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

6 0

Answer:

P ( 3, - pi/3 + 2 pi n) or P ( -3 , -pi/3 + pi(2 n +1))

Step-by-step explanation:

P ( 3, - pi/3)

We can circle 2pi n around the circle and be back at the same polar coordinate

P ( 3, - pi/3 + 2 pi n)

or we can flip the radius to a negative and add pi to the theta

P ( -3, - pi/3 + pi)

Then we can circle 2pi n around the circle and be back at the same polar coordinate

P ( -3 , -pi/3 + 2 pi n +pi)

P ( -3 , -pi/3 + pi(2 n +1))

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The surface area (SA) of a cube can be written as:

SA = 6s²

From here we can write, the length of the side s as:

$s= \sqrt{ \frac{SA}{6} }$

For cube with surface area of 1200 square inches, the side length will be:

$s= \sqrt{ \frac{1200}{6} }=10 \sqrt{2}$ inches

For cube with surface area 768 square inches, the side length will be:

$s= \sqrt{ \frac{768}{6} }=8 \sqrt{2}$ inches

The difference in side lengths of two cubes will be:

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