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grigory [225]
3 years ago
13

5 times 8/7 FOR MAtH

Mathematics
2 answers:
joja [24]3 years ago
6 0

Answer: 40/7 as a fraction, 5 5/7 as improper fraction

5.7 as decimal

Step-by-step explanation:

aleksklad [387]3 years ago
4 0

Answer:

40/7  =   5 5/7

Step-by-step explanation:

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Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i
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\huge \boxed{\mathfrak{Answer} \downarrow}

\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\

Multiply both numerator and denominator of \sf \frac{5-3i}{-2-9i} \\ by the complex conjugate of the denominator, -2+9i.

\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)})  \\

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\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}})  \\

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\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85})  \\

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\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85})  \\

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\large \bf \: Re(\frac{-10+45i+6i+27}{85})  \\

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\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85})  \\

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\large \bf Re(\frac{17+51i}{85})  \\

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\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i)  \\

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\large  \boxed{\bf\frac{1}{5} = 0.2} \\

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