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zalisa [80]
3 years ago
11

Jordan is kayaking upstream. The following equation models his speed: f(x) = 2x2 − 4x − 9, where x is Anna's speed relative to l

and. What is the domain of the function? x ≥ 1 x ≤ −4 x ≥ −9 All real numbers
Mathematics
1 answer:
andrew11 [14]3 years ago
5 0

Answer:

All real numbers

Step-by-step explanation:

The given equation is:

f(x) = 2 {x}^{2}   - 4x - 9

where x is Ana's speed.

This is a quadratic function.

A quadratic function is a polynomial function.

All polynomial functions are are continuous and defined for all real values of x.

Therefore the domain of

f(x) = 2 {x}^{2}   - 4x - 9

is all real numbers.

You might be interested in
2. What is the x-value to the solution for the system of equations y = -5x - 9 and y = 2x<br> + 5.
pav-90 [236]

Answer:

The x-value is -2

Step-by-step explanation:

U can substitute any of the equations for y

-5x + (-9) = 2x + 5

-9 = 7x + 5

-14 = 7x

-2 = x

x = 2

7 0
3 years ago
4. In a women's professional tennis tournament, the money a player wins depends on her finishing place in the
Stels [109]

Using geometric sequence concepts, it is found that:

a) The rule is: P_n = 750000(0.5)^{n-1}.

b) An exponential relationship exists between the two variables.

<h3>What is a geometric sequence?</h3>

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

a_n = a_1q^{n-1}

In which a_1 is the first term.

A geometric sequence represents an exponential relationship between the variables.

In this problem, considering that the first-place finisher wins half of $1.500.000 in total prize money, and each finisher earns half of the one who finished above, the first term and the common ratio are given by:

a_1 = 750000, q = 0.5.

Hence the nth term of the sequence is given by:

P_n = 750000(0.5)^{n-1}

More can be learned about geometric sequence concepts at brainly.com/question/11847927

#SPJ1

4 0
2 years ago
I need help figuring this out can someone help me
Reil [10]
I think the answer is b
4 0
3 years ago
Read 2 more answers
Answer for brainliest
AlladinOne [14]

Answer:

plu this in on MATHHHHHHHHHH WAYYYYYYYYY (i cant put in the actual site) but use it it will tell u answers!

Step-by-step explanation:

5 0
3 years ago
The scores of students on the ACT college entrance exam in a recent year had the normal distribution with mean  =18.6 and stand
Maurinko [17]

Answer:

a) 33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) 0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 18.6, \sigma = 5.9

a) What is the probability that a single student randomly chosen from all those taking the test scores 21 or higher?

This is 1 subtracted by the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 18.6}{5.4}

Z = 0.44

Z = 0.44 has a pvalue of 0.67

1 - 0.67 = 0.33

33% probability that a single student randomly chosen from all those taking the test scores 21 or higher.

b) The average score of the 76 students at Northside High who took the test was x =20.4. What is the probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher?

Now we have n = 76, s = \frac{5.9}{\sqrt{76}} = 0.6768

This probability is 1 subtracted by the pvalue of Z when X = 20.4. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{20.4 - 18.6}{0.6768}

Z = 2.66

Z = 2.66 has a pvalue of 0.9961

1 - 0.9961 = 0.0039

0.39% probability that the mean score for 76 students randomly selected from all who took the test nationally is 20.4 or higher

4 0
3 years ago
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