I think this answer, "<span>Upload all existing documents to a cloud-based program," is correct. Hope I helped!!</span>
Answer:
import java.lang.Object
import java.lang.Math
public class RegularPolygon extends java.lang.Object{
public void randomize(RegularPolygon c){
int min = 10, max1 = 20;
double min1 = 5, max1 = 12;
double range = (max - min) + 1;
double range1 = (max1 -min1) + 1
int side = (Math.random() * range) + min;
double len = (Math.random() * range1) + min1;
c.setNumSides(side);
c.setSideLength( len);
}
public static void main(String[] args) {
RegularPolygon r = new RegularPloygon();
randomize(r);
}
}
Explanation:
The randomize method accepts a regular polygon class as its only parameter and assigns a random number of sides and the length of these sides with the 'Math.random' function.
Answer:
#include <bits/stdc++.h>
using namespace std;
bool isPalindrome(string str)
{
char a,b;
int length = str.length();
for (int i = 0; i < length / 2; i++)
{
a=tolower(str[i]);//Converting both first characters to lowercase..
b=tolower(str[length-1-i]);
if (b != a )
return false;
}
return true;
}
int main() {
string t1;
cin>>t1;
if(isPalindrome(t1))
cout<<"The string is Palindrome"<<endl;
else
cout<<"The string is not Palindrome"<<endl;
return 0;
}
Output:-
Enter the string
madam
The string is Palindrome
Enter the string
abba
The string is Palindrome
Enter the string
22
The string is Palindrome
Enter the string
67876
The string is Palindrome
Enter the string
444244
The string is not Palindrome
Explanation:
To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.
Yes the ansewer is c bc you can look it up!
