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Daniel [21]
2 years ago
13

Barry wants to take out a loan from his bank for $1,000 to buy a bicycle. The interest rate on the loan from the bank is 9%. He

wants to pay the total amount in 3 monthly payments. What is the amount that Barry would pay in interest for his loan?
Mathematics
1 answer:
tekilochka [14]2 years ago
3 0

Answer:

The amount that Barry would pay in interest for his loan is $15.05.

Step-by-step explanation:

To calculate this, we first calculate the monthly required fixed payment using the formula for calculating loan amortization as follows:

P = (A * (r * (1 + r)^n)) / (((1+r)^n) - 1) .................................... (1)

Where,

P = Monthly required fixed payment = ?

A = Loan amount = $1,000

r = monthly interest rate = 9% / 12 = 0.09 / 12 = 0.0075

n = number of payment months = 3

Substituting all the figures into equation (1), we have:

P = ($1,000 * (0.0075 * (1 + 0.0075)^3)) / (((1 + 0.0075)^3) - 1)

P = $338.35

Therefore, we have:

Total repayment = P * 3 months = $338.35 * 3 = $1,015.05

Interest amount = Total repayment - Loan principal = $1,015.05 - $1,000 = $15.05.

Therefore, the amount that Barry would pay in interest for his loan is $15.05.

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Which of the following is a polynomial with rootsnegative square root of 5, square root of 5, and 3
Scrat [10]

Answer:

P(x) = x³ - 3x² - 5x + 15

Step-by-step explanation:

∵ The roots of the polynomial are -√5 , √5 , 3

∴ The polynomial has 3 factors:

  (x - √5) , (x + √5) , (x - 3)

∴ P(x) = (x - √5)(x + √5)(x - 3)

          = (x² + √5x - √5x - 5)(x - 3)

          = (x² - 5)(x - 3) = x³ - 3x² - 5x + 15

∴ P(x) = x³ - 3x² - 5x + 15

3 0
2 years ago
URGENT will give brilliant mark For the reaction 2Na + Cl2 ------ 2NaCl, how many grams of sodium chloride can be produced from
SVETLANKA909090 [29]

Answer:

825 g

Step-by-step explanation:

Here's my work:

500g Cl2 l   1mol Cl2  l  2 mol NaCl   l  58.5 g NaCl

                l   71 g Cl2    l  1 mol Cl2      l    1 mol NaCl  

= 823.94  - the rounding can be a little off

The first thing you have to do is convert the 500 g of Cl2 into moles.  So you get the mass of Cl which is 35.5, but Cl is diatomic by itself so you multiply 35.5 x 2 and get 71.   now on the third column you are comparing the mol ratios of the equation.  The equation is 2Na + Cl2 ---> 2NaCl, so you see that there is no coefficient in front of Cl2 so that means there is 1 mol, and then you see that in the product there is a  coefficient of 2 in front of NaCl so that means there is 2 moles.  Then finally you have to convert the moles backs into grams where you just add the masses of Na and Cl .  You multiply across the top  and then divide that number by the bottom row.

6 0
2 years ago
Jess wants to measure how much water she uses in the shower each morning. She finds
forsale [732]

Answer:

32 gallons of water

Step-by-step explanation:

8 minutes = 480 seconds.

set up a proportion:

1/15=x/480

we have to solve for x:

15x=480

x=32.

Jess uses 32 gallons of water.

6 0
3 years ago
Read 2 more answers
Is a circle a function?
Anit [1.1K]

Answer:

No, Each input has one output

Step-by-step explanation:

A circle can't be a function because of its radius and diameter, its not linear so  it might have the same input or output. Therefore, you need a line to have a linear function .!

Pls mark brainiest!

I hope you get this right!

3 0
3 years ago
4x+y+2z=4<br> 5x+2y+z=4<br> x+3y=3
vekshin1

Objective: Solve systems of equations with three variables using addition/elimination.

Solving systems of equations with 3 variables is very similar to how we solve systems with two variables. When we had two variables we reduced the system down

to one with only one variable (by substitution or addition). With three variables

we will reduce the system down to one with two variables (usually by addition),

which we can then solve by either addition or substitution.

To reduce from three variables down to two it is very important to keep the work

organized. We will use addition with two equations to eliminate one variable.

This new equation we will call (A). Then we will use a different pair of equations

and use addition to eliminate the same variable. This second new equation we

will call (B). Once we have done this we will have two equations (A) and (B)

with the same two variables that we can solve using either method. This is shown

in the following examples.

Example 1.

3x +2y − z = − 1

− 2x − 2y +3z = 5 We will eliminate y using two different pairs of equations

5x +2y − z = 3

1

3x +2y − z = − 1 Using the first two equations,

− 2x − 2y +3z = 5 Add the first two equations

(A) x +2z = 4 This is equation (A), our first equation

− 2x − 2y +3z = 5 Using the second two equations

5x +2y − z = 3 Add the second two equations

(B) 3x +2z = 8 This is equation (B), our second equation

(A) x +2z = 4 Using (A) and (B) we will solve this system.

(B) 3x +2z = 8 We will solve by addition

− 1(x +2z) =(4)( − 1) Multiply (A) by − 1

− x − 2z = − 4

− x − 2z = − 4 Add to the second equation, unchanged

3x +2z = 8

2x = 4 Solve, divide by 2

2 2

x = 2 We now have x! Plug this into either(A) or(B)

(2) +2z = 4 We plug it into (A),solve this equation,subtract 2

− 2 − 2

2z = 2 Divide by 2

2 2

z = 1 We now have z! Plug this and x into any original equation

3(2) +2y − (1)= − 1 We use the first, multiply 3(2) =6 and combine with − 1

2y + 5= − 1 Solve,subtract 5

− 5 − 5

2y = − 6 Divide by 2

2 2

y = − 3 We now have y!

(2, − 3, 1) Our Solution

As we are solving for x, y, and z we will have an ordered triplet (x, y, z)

5 0
3 years ago
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