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viktelen [127]
4 years ago
10

A simple random sample has a sample size of n=65. Given the population is normally distributed, find the critical value t_a/2 co

rresponding to a 99% confidence level.
Mathematics
1 answer:
Dmitry [639]4 years ago
6 0

Answer:

2.6549

Step-by-step explanation:

Since the sample size n=65, the degrees of freedom is n-1=65-1=64

The critical value=\frac{t_{0.01}}{2}=t_{0.005}

Using the t-table and selecting df=64 and \alpha=0.01 since it’s a 2 tail the corresponding t-score is 2.6549

Therefore, the critical value is 2.6549

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Whats the answer to g/2-9=-7
andrew11 [14]

Answer:

Step-by-step explanation:

g/2-9=-7

inverse operation:

g/2-9=-7

      +9 +9

g/2=2

g/2=2*2

g = 4

7 0
4 years ago
Read 2 more answers
What transformation rule would represent a shift of 3 units to the left 4 units down?
Llana [10]

Given:

Shift of 3 units to the left 4 units down.

To find:

The transformation rule.

Solution:

The rule of transformation is

(x,y)\to (x+a,y+b)          ...(i)

Here, a<0 if the figure shifts a units left and a>0 if the figure shifts a units right.

Similarly, b<0 if the figure shifts b units down and b>0 if the figure shifts b units up.

If a transformation represents shift of 3 units to the left 4 units down, then a=-3 and b=-4.

Putting a=-3 and b=-4 (i), we get

(x,y)\to (x+(-3),y+(-4))

(x,y)\to (x-3,y-4)

Therefore, the correct option is B.

4 0
3 years ago
How do you solve 3 x 3 1/3
Butoxors [25]

Answer:

10

Step-by-step explanation:

Turn 3 1/3 into an improper fraction.

(3*3) + 1 = 10/3    so 10/3 is the same as 3 1/3

Turn the 3 into an improper fraction of 3/1

Now multiply 10/3 * 3/1  multiplying straight across: 10*3/3*1=30/3=10

4 0
4 years ago
Find the equation of all tangent lines having slope of -1 that are tangent to the curve y=(9)/(x+1)
fredd [130]

Answer:

f(x)=\frac9{x+1}\\ f'(x)=-\frac9{(x+1)^2}\\ f'(x)=-1\ \iff\ -\frac9{(x+1)^2}=-1\ \to \ \frac9{(x+1)^2}=1\ \to \ (x+1)^2=9\\ |x+1|=3\ \to \ x+1=3\ \vee\ x+1=-3\\ x_1=2\ \vee\ x_2=-4\\ f(x_1)=f(2)=\frac9{2+1}=3\\ f(x_2)=f(-4)=\frac9{-4+1}=-3

First tangent line:

y=f'(x_1)\cdot (x-x_1)+f(x_1)\ \to \ y=-1(x-2)+3\ \to \ y=-x+5

Second tangent line:

y=f'(x_2)\cdot (x-x_2)+f(x_2)\ \to \ y=-1(x+4)-3\ \to \ y=-x-7


Notice: slope of -1 means that both f'(x_1), \ f'(x_2) are equal to -1, so f'(x_1)=-1 \ and \ f'(x_2)=-1


6 0
3 years ago
Read 2 more answers
Mike wants to save $1,750 in the next 12 months. He plans to save $150 each month for the first 11 months.
podryga [215]

Answer:

$1650

Step-by-step explanation:

Based on the question, we don't need the information that Mike wants to save 1750 in 12 months.

We just need to focus on how he is saving 150 every month, for 11 months.

150*11=1650

He will save $1650 if he saves $150 every month for 11 months.

3 0
3 years ago
Read 2 more answers
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