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fgiga [73]
2 years ago
12

Please help me pre algebra 8th gradeee

Mathematics
1 answer:
Ratling [72]2 years ago
7 0

answer :

<em>Front & back</em>

explanation :

<em>Area = lw </em>

<em>    ( length x width ) </em>

<em></em>

<em>CORRECT </em>

<em>Front: 4 x 7 = 28 </em>

<em>Back:  4 x 7 = 28</em>

<em></em>

<em>INCORRECT </em>

<em>Bottom: 7 x 9 = 63 </em>

<em>Top: 7 x 9 = 63</em>

<em>Right: 4 x 9 = 36</em>

<em>Left: 4 x 9 = 36 </em>

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Tony tacos is selling 15 sodas for 10 dollars.Nicks nachos is selling 30 sodas for 20dollars. Write the ratios.Are the two ratio
Mandarinka [93]

Answer: The ratios are proportional

Step-by-step explanation:

Tony tacos is selling 15 sodas for 10 dollars.

Nicks nachos is selling 30 sodas for 20dollars. The ratio of the number sodas sold by Tony tacos to the number of sodas sold by Nicks nachos is 15/30 = 1/2

The ratio of the cost of sodas sold by Tony tacos to the cost of sodas sold by Nicks nachos is 10/20 = 1/2

So the number of sodas sold is proportional to the cost.

8 0
3 years ago
The wind is blowing N 35.0 degrees W at 1.60 * 10^2 mph. A plane has an engine speed of 3.20 * 10^2 mph. Where should the pilot
andreyandreev [35.5K]

Answer: 24.2° SouthWest

<u>Step-by-step explanation:</u>

First step: DRAW A PICTURE of the vectors from head to tail <em>(see image)</em>

I created a perpendicular from the resultant vector to the vertex of the given vectors so I could use Pythagorean Theorem to find the length of the perpendicular. Then I used that value to find the angle of the plane.

<u>Perpendicular (x):</u>

 cos 35° = adjacent/hypotenuse

  cos 35° = x/160

→ x = 160 cos 35°

<u>Angle (θ):</u>

sin θ = opposite/hypotenuse

sin θ = x/320

sin θ = 160 cos 35°/320

    θ = arcsin (160 cos 35°/320)

    θ = 24.2°

Direction is down (south) and left (west)

7 0
3 years ago
SORRY! BUT ALL HELP IS REALLY APPRECIATED! AND WOULD LIKE IF YOU COULD HELP A GURL OUT THANKS
Korolek [52]

Answer:

b is the answer trust me i know

Step-by-step explanation:

6 0
3 years ago
I am stuck at this question​
Marrrta [24]

Answer:

Step-by-step explanation:

B(2,10); D(6,2)

Midpoint(x1+x2/2, y1+y2/2) = M ( 2+6/2, 10+2/2) = M(8/2, 12/2) = M(4,6)

Rhombus all sides are equal.

AB = BC = CD =AD

distance = √(x2-x1)² + (y2- y1)²

As A lies on x-axis, it y-co ordinate = 0; Let its x-co ordinate be x

A(X,0)

AB = AD

√(2-x)² + (10-0)² = √(6-x)² + (2-0)²

√(2-x)² + (10)² =  √(6-x)² + (2)²

√x² -4x +4 + 100 =  √x²-12x+36 + 4

√x² -4x + 104 =  √x²-12x+40

square both sides,

x² -4x + 104 =  x²-12x+40

x² -4x - x²+ 12x = 40 - 104

             8x = -64

               x = -64/8

               x = -8

A(-8,0)

Let C(a,b)

M is AC midpoint

(-8+a/2, 0 + b/2)  = M(4,6)

     (-8+a/2, b/2)  = M(4,6)

Comparing;  

-8+a/2 = 4          ; b/2 = 6

  -8+a = 4*2       ; b = 6*2

  -8+a = 8          ; b = 12

        a = 8 +8

       a = 16

Hence, C(16,12)

6 0
3 years ago
a buret is a tool designed to transfer precise amounts of liquid .A buret initially contains 70.00 millimeters of a solution and
katrin [286]

Let:

Vbu= Volume of the buret

Vbk= Volume of the beaker

A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution, therefore:

x = Number of drips

a = volume of each drip

\begin{gathered} Vbu=70-ax \\ Vbk=20+ax \\ \text{where:} \\ a=0.05 \\ Vbu=70-0.05x \\ Vbk=20+0.05x \end{gathered}

after how many drips will the volume of the solution in the buret and beaker be equal ?​ Vbu = Vbk:

\begin{gathered} Vbu=Vbk \\ 70-0.05x=20+0.05x \\ \text{Solve for x:} \\ 0.1x=70-20 \\ 0.1x=50 \\ x=\frac{50}{0.1} \\ x=500 \end{gathered}

5 0
1 year ago
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