Answer:
20 minutes
Step-by-step explanation:
Remember that
![1\ h=60\ mi](https://tex.z-dn.net/?f=1%5C%20h%3D60%5C%20mi)
we know that
Hector has 3/4 hour to spend his homework
Convert to minutes
![\frac{3}{4}(60)=45\ min](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%2860%29%3D45%5C%20min)
so
1) He wants to spend 1/3 of this time on math homework
To find out the time on math homework, multiply 45 minutes by 1/3
![45(\frac{1}{3})=15\ min](https://tex.z-dn.net/?f=45%28%5Cfrac%7B1%7D%7B3%7D%29%3D15%5C%20min)
2) He wants to spend 10 minutes of his time on reading homework
3) He wants to spend the remaining time on science homework
The time spend on math homework plus the time spend reading homework, plus the time spend on his science homework must be equal to 45 minutes
Let
x ----> the time spend on his science homework
![15+10+x=45](https://tex.z-dn.net/?f=15%2B10%2Bx%3D45)
Solve for x
![25+x=45\\x=45-25\\x=20\ min](https://tex.z-dn.net/?f=25%2Bx%3D45%5C%5Cx%3D45-25%5C%5Cx%3D20%5C%20min)
Answer:
it's going to be 4n so its going to be 4...
Step-by-step explanation:
The points (0, 3), (4, 0), (9, 0), (0, 11), and (14, 0) are plotted on the graph. On a coordinate plane, points (0, 3), (4, 0),
Advocard [28]
Answer:
can you take a picture it might make it easier for me
Answer:
The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units
Therefore distance s=10 units
Step-by-step explanation:
Given points are (2,10) and (-6, 4) on the coordinate plane
To distance between the given points :
The distance formula is
units
Let
,
be the given points (2,10) and (-6, 4) respectively
Now substituting the values in the distance formula we get
![=\sqrt{8^2+6^2}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B8%5E2%2B6%5E2%7D)
![=\sqrt{64+36}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B64%2B36%7D)
![=\sqrt{100}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B100%7D)
![=10](https://tex.z-dn.net/?f=%3D10)
Therefore s=10 units
The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units
![log_{x}(1/8)=-3/2](https://tex.z-dn.net/?f=log_%7Bx%7D%281%2F8%29%3D-3%2F2)
This is equal to...
![x^{-3/2}=1/8](https://tex.z-dn.net/?f=x%5E%7B-3%2F2%7D%3D1%2F8)
We want "x" so we need to isolate it using laws of exponents...
![x^{(-1)(3/2)}=1/8](https://tex.z-dn.net/?f=x%5E%7B%28-1%29%283%2F2%29%7D%3D1%2F8)
because ![x^{-a}=1/x^{a}](https://tex.z-dn.net/?f=x%5E%7B-a%7D%3D1%2Fx%5E%7Ba%7D)
because ![x^{a/b}=\sqrt[b]{x^{a}}](https://tex.z-dn.net/?f=x%5E%7Ba%2Fb%7D%3D%5Csqrt%5Bb%5D%7Bx%5E%7Ba%7D%7D)
x = 4
answer: B