WILL GIVE BRAINIEST TO THE PERSON THAT ANSWERS ALL THREE QUESTIONS ASAP!

Mathematics

2 answers:

Radda [10]3 years ago

8 0

Answer:

1. Your answer would be C) 2√3-5√2.

2. Your answer would be -39.7i.

3. Your answer would be -1.

Step-by-step explanation:

bagirrra123 [75]3 years ago

3 0

Answer:

First:

$\sqrt{2} (\sqrt{6} -\sqrt{10} )$ simplified is your bottom answer D.

$-6i\sqrt{-44}$ simplified is $12\sqrt{11}$

$i^{72}$ simplified is -1

Step-by-step explanation:

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Y=-4x-2 and intersects at the points (4,-1)

rosijanka [135]

Answer:

It doesn't intersect at that point

${ \bf{y = - 4x - 2}} \\ y = - (4 \times 4) - 2 \\ y = - 18$

4 0

2 years ago

Read 2 more answers

Express this to single logarithm

zzz [600]

Answer: $\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)$

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

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Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

log(A) + log(B) = log(A*B)
log(A) - log(B) = log(A/B)
B*log(A) = log(A^B)

From there, we can then say the following:

$\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}$