Which is equivalent to ^3v8^ 1/4
1 answer:
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Answer: 5y + 4x = - 10
Step-by-step explanation:
Two lines are said to be perpendicular if the product of their gradients = -1.
If the gradient of the first line is and the gradient of the second line is
, if the lines are perpendicular, them
x
= -1 , that is
=
The equation of the line given is 5x - 4y = -3 , we need to write this equation in slope - intercept form in order to find the slope.
The equation in slope -intercept form is given as :
y =mx + c , where m is the slope and c is the y - intercept.
Writing the equation in this form , we have
5x - 4y = + 3
4y = 5x -+3
y = 5x/4 + 3/4
comparing with the equation y = mx + c , then = 5/4
Which means that = -4/5 and the line passes through the point ( -5 , 2 ).
Using the equation of line in slope - point form to find the equation of the line;
y - = m ( x -
)
y - 2 = -4/5 ( x +5)
5(y - 2 ) = -4 ( x + 5 )
5y - 10 = -4x - 20
5y + 4x = - 10
The probability that the SRS of 10 students will spend an average of between 600 and 700 dollars is 0.8132.
Let x be the total amount spent by students.
x follows normal distribution with mean μ = 650,
standard deviation δ = 120
We take a simple random sample of size n = 10
We are asked to find average spending of 10 students ( ) is between 600 and 700
We have to find P( 600 <= <= 700)
According to the sampling distribution of the sample mean , it follows an approximately normal distribution with mean μ{
} = μ and standard deviation δ{
} = {δ}/{√n}
Therefore here mean of ,( μ{
} ) = 650 and
standard deviation of , δ{
} = {120}/{√10} = 37.9473
The probability that the SRS of 10 students will spend an average of between 600 and 700 dollars is,
Let Z= x - μ / δ
Z₁ = 600 - 650 / 37.9473 = -1.32 similarly
Z₂ = 700 - 650 / 37.9473 = 1.32
From standard normal distribution table, P( -1.32 < < 1.32) = 0.8132
The probability that the SRS of 10 students will spend an average of between 600 and 700 dollars is 0.8132
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