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matrenka [14]
3 years ago
10

during a 500-meter race, a runner ran the first 400 meters in 1 minute and 25 seconds.she finished the race i 2 minutes and 15 s

econds. what was her average rate of change during the last 100 meters of the race as a decimal
Mathematics
1 answer:
mart [117]3 years ago
6 0

She ran the last 100 meters in 2:15 -1:25 = 0:50, so her average speed was

... (100 m)/(50 s) = 2.0 m/s

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Simplify (tan^2 x/sec x + 1) + 1
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PLEASE HELP ME! !!!!!!
Makovka662 [10]

Answer:The height of the building which caste a shadow 20.5 m in length is 17.5 m.          

Step-by-step explanation:

Given : At a particular time of a day, a 7 high flagstaff castes a shadow which is 8.2 m long.

To find : What is the height of the building which castes a shadow 20.5 meters in length at the same moment?

Solution :

A 7 high flagstaff castes a shadow which is 8.2 m long.

i.e. Shadow of length 8.2 m = 7 m

The shadow of length 1 m =  m

The shadow of length 20.5 m =  m

The shadow of length 20.5 m = 17.5 m

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8 0
3 years ago
A sample of 2,000 licensed drivers revealed the following number of speeding violations. Number of Violations Number of Drivers
Arturiano [62]

Answer:

The probability that a particular driver had exactly two speeding violations is 0.009.

Step-by-step explanation:

We are given that a sample of 2,000 licensed drivers revealed the following number of speeding violations;

           <u>Number of Violations</u>               <u>Number of Drivers</u>

                         0                                              1,910

                          1                                                46

                         2                                                 18

                         3                                                 12

                         4                                                  9

                         5 or more                             <u>       5      </u>

                        <u>Total</u>                                      <u>    2000  </u>

<u />

Now, the data means that 1,910 drivers had 0 speeding violations and so on.

Now, we have to find the probability that a particular driver had exactly two speeding violations, that means;

Number of drivers having exactly two speeding violations = 18

 Total numbers of drivers = 2000

So, the required probability  =  \frac{\text{No. of drivers having two speeding violations}}{\text{Total no. of drivers}}

                                               =  \frac{18}{2000}  =  <u>0.009</u>

6 0
3 years ago
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