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Svetlanka [38]
2 years ago
11

Free piont (so this will not get delete) 7x8x3=

Mathematics
2 answers:
ruslelena [56]2 years ago
6 0

Answer:

168 also thank you so much

Step-by-step explanation:

SVEN [57.7K]2 years ago
5 0

Answer:

168

Step-by-step explanation:

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7. Find the inverse of f(x) = -2x + 10. Please show work.​
Kipish [7]

Answer- y = - x/2 + 5

Step by step - Replace f (x) with y.

Y = - 2x + 10

Interchange the variables.

x= -2y + 10

Solve for y.

Y= x/2 +5

8 0
2 years ago
Power Series Differential equation
KatRina [158]
The next step is to solve the recurrence, but let's back up a bit. You should have found that the ODE in terms of the power series expansion for y

\displaystyle\sum_{n\ge2}\bigg((n-3)(n-2)a_n+(n+3)(n+2)a_{n+3}\bigg)x^{n+1}+2a_2+(6a_0-6a_3)x+(6a_1-12a_4)x^2=0

which indeed gives the recurrence you found,

a_{n+3}=-\dfrac{n-3}{n+3}a_n

but in order to get anywhere with this, you need at least three initial conditions. The constant term tells you that a_2=0, and substituting this into the recurrence, you find that a_2=a_5=a_8=\cdots=a_{3k-1}=0 for all k\ge1.

Next, the linear term tells you that 6a_0+6a_3=0, or a_3=a_0.

Now, if a_0 is the first term in the sequence, then by the recurrence you have

a_3=a_0
a_6=-\dfrac{3-3}{3+3}a_3=0
a_9=-\dfrac{6-3}{6+3}a_6=0

and so on, such that a_{3k}=0 for all k\ge2.

Finally, the quadratic term gives 6a_1-12a_4=0, or a_4=\dfrac12a_1. Then by the recurrence,

a_4=\dfrac12a_1
a_7=-\dfrac{4-3}{4+3}a_4=\dfrac{(-1)^1}2\dfrac17a_1
a_{10}=-\dfrac{7-3}{7+3}a_7=\dfrac{(-1)^2}2\dfrac4{10\times7}a_1
a_{13}=-\dfrac{10-3}{10+3}a_{10}=\dfrac{(-1)^3}2\dfrac{7\times4}{13\times10\times7}a_1

and so on, such that

a_{3k-2}=\dfrac{a_1}2\displaystyle\prod_{i=1}^{k-2}(-1)^{2i-1}\frac{3i-2}{3i+4}

for all k\ge2.

Now, the solution was proposed to be

y=\displaystyle\sum_{n\ge0}a_nx^n

so the general solution would be

y=a_0+a_1x+a_2x^2+a_3x^3+a_4x^4+a_5x^5+a_6x^6+\cdots
y=a_0(1+x^3)+a_1\left(x+\dfrac12x^4-\dfrac1{14}x^7+\cdots\right)
y=a_0(1+x^3)+a_1\displaystyle\left(x+\sum_{n=2}^\infty\left(\prod_{i=1}^{n-2}(-1)^{2i-1}\frac{3i-2}{3i+4}\right)x^{3n-2}\right)
4 0
3 years ago
Hi can someone help me with this geo question please thanks
IrinaVladis [17]

Answer:

x = 24 , y = 19

Step-by-step explanation:

(2x + 13) and 47 + 3x are same- side interior angles and sum to 180° , so

2x + 13 + 47 + 3x = 180 , that is

5x + 60 = 180 ( subtract 60 from both sides )

5x = 120 ( divide both sides by 5 )

x = 24

Then 3x = 3 × 24 = 72

5y - 23 and 3x are corresponding angles and are congruent , then

5y - 23 = 72 ( add 23 to both sides )

5y = 95 ( divide both sides by 5 )

y = 19

7 0
2 years ago
Find an equation of the line that passes through the points (5,- 4) and (2,-2).
Andru [333]

Answer:

y=-2/3x - 2/3

Step-by-step explanation:

4 0
2 years ago
Solve for y Y/3 + 25 = 31
ruslelena [56]

Answer:

y = 18

Step-by-step explanation:

8 0
2 years ago
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