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mariarad [96]
3 years ago
12

a carpenter who is installing cabinets uses thin pieces of material called shims to fill gaps. the carpenter uses four shims to

fill a gap that is 1.2 centimeters wide. three of the shims are 0.75 centimeter, 0.125 centimeter, and 0.09 centimeter wide. What is the width of the fourth shim?
Mathematics
1 answer:
sukhopar [10]3 years ago
3 0


Add up all the shims lengths that you know of right now

.75 + .125 + .09 = ?

That equals .965

The fourth shim is how ever many more centimeter until 1.2


To find this out... subtract

1.2 - .965

Your answer to this equation would be the length of the fourth shim.

1.2 - .965 = .235


The fourth shim is .235 centimeters long :)

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8 0
3 years ago
50,60,72 find the 8th term airthmetic and geometric sequence
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Answer:

8th term is 179.15904

Step-by-step explanation:

The sequence is geometric with a common ration = 6/5

r = 60/50 = 72/60 = 6/5

Use the formula

a_{n} = ar^{n - 1}

In your case a = 50, r = 6/5 and n = 8

a_{8} = 50(6/5)^{8 - 1} \\          = 50(6/5)^{7} \\          =  50(279936/78125)\\          =   179.15904

4 0
3 years ago
1.<br> Explain why the diagram shows that 6 (3 + 4) = 6*3 + 6*4
anygoal [31]

Answer:

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5 0
3 years ago
If the units digit of the three-digit positive integer k is nonzero, what is the tens digit of k ?
Vanyuwa [196]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a stand
Art [367]

Answer:

b. Mean = 1.6 years, standard deviation - 0.92 years, shape: approximately Normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal Variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a standard deviation of 4.2 years. Sample of 35:

This means that:

\mu_G = 15

s_G = \frac{4.2}{\sqrt{35}} = 0.71

The distribution of life spans for electric ranges has a mean of 13.4 years and a standard deviation of 3.7 years. Sample of 40:

This means that:

\mu_E = 13.4

s_E = \frac{3.7}{\sqrt{40}} = 0.585

Which of the following best describes the sampling distribution of the difference in mean life span of gas ranges and electric ranges?

Shape is approximately normal.

Mean:

\mu = \mu_G - \mu_E = 15 - 13.4 = 1.6

Standard deviation:

s = \sqrt{s_G^2+s_E^2} = \sqrt{0.71^2+0.585^2} = 0.92

So the correct answer is given by option b.

8 0
3 years ago
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