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NNADVOKAT [17]
3 years ago
8

If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how

much gasoline is used per year for all of the cars, assuming an average gas mileage of 40 miles per gallon? Provide your answer in litres in scientific notation to 2 decimal places. Show all your work.
Mathematics
1 answer:
Goryan [66]3 years ago
4 0

Rates are used to measure a quantity over another.

<em>The 1.8 million cars use </em>1.85 \times 10^{10}<em> liters each year</em>

Given

Cars = 1.8\ million

d = 17500km --- distance

r = 40miles/gallon

First, we calculate the number (n) of gallons used by each car

r = \frac{d}{n}

Solve for n

n = \frac{d}{r}

So, we have:

n = \frac{17500km}{40miles/gallon}

n = \frac{17500km}{40miles}gallon

Convert miles to kilometers

n = \frac{17500km}{40km \times 1.60934}gallon

n = \frac{17500km}{64.3738km}gallon

n = 271.85\ gallon

The number of gallons (N), used by all the cars is:

N = n \times cars

N = 271.85 \times 1.8\ million

N = 489330000

Convert to liters

N = 489330000 \times 3.78541L

N = 1852314675.3L

In scientific notation to 2 decimal places, we have:

N = 1.85 \times 10^{10}L

<em>Hence, the number of liters used is </em>1.85 \times 10^{10}<em />

Read more about distance and rates at:

brainly.com/question/24659604

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Step-by-step explanation:

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The answer in the attached figure

Step-by-step explanation:

Let

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Virty [35]

Answer:

They would meet each other at 01 : 24 PM.

Step-by-step explanation:

  • Erik took a trip to see his friend Mike who lives 308 miles away.
  • He left his place at 10 AM driving at 70 mph.
  • In 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph.

As Erik left his house at 10 AM driving at 70 mph and in 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph. It means

Erik left his place at 12:00 PM noon.

so, at 12:00 PM Erik had already traveled:

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Miles left =308-140=168\:\:miles

Let 't' be the time when they meet

so

70t\:+\:50t\:=168

120t=168

\mathrm{Divide\:both\:sides\:by\:}120

\frac{120t}{120}=\frac{168}{120}

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Therefore, they would meet each other at 01 : 24 PM.

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