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2 years ago

How do I solve 34 x 17 using an area model

Mathematics

1 answer:

givi [52]2 years ago

4 0

Multiplying 34x 17 and you will get answer

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Aiko jump rope for an amazing 20 min she stopped at 8:05 when did she start

Scrat [10]

Aiko jump roped for 20 minutes before stopping at 8:05. Just count 20 minutes back in order to see when she started.

8:05 - 20 minutes = 7:45

6 0

2 years ago

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Write the equation of the line that goes through (-2, 0) and (4,3).

Snezhnost [94]

Answer:

Step-by-step explanation:

I just put in in the desmos graphing calculator

8 0

2 years ago

What is the equation of the sinusoid shown in the graph?

ololo11 [35]

Answer:

Answer: C

Step-by-step explanation:

The Cosine Function

The graph of a cosine function is a sinusoid that starts at its maximum value of 1 at x=0 and takes x=2π radians to complete a full cycle. The function of the parent cosine function is:

$y=\cos x$

Both the amplitude A and the angular frequency w of a cosine can be modeled by the function

$y=A\cos(\omega x)$

The graph of the cosine function shown in the figure has an amplitude of A=3 and it completes a full cycle at x=π/2, thus:

$\frac{\pi}{2}\omega =2\pi$

Thus:

$\omega = 4$

Therefore, the equation of the sinusoid is:

$y=3\cos (4x)$

Answer: C

3 0

2 years ago

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3(4x^2y^3 + 2x^3) – 4(9x^3y^2 – 6x^2y^3) How to solve pls?

babunello [35]

Answer:

$3(4 {x}^{2} {y}^{3} + 2 {x}^{3}) - 4(9 {x}^{3} {y}^{2} - 6 {x}^{2} {y}^{3} ) \\ = (12 {x}^{2} {y}^{3} + 6 {x}^{3} ) - (36{x}^{3} {y}^{2} - 24{x}^{2} {y}^{3}) \\ = (12 {x}^{2} {y}^{3} + 6 {x}^{3} ) + ( - 36{x}^{3} {y}^{2} + 24{x}^{2} {y}^{3}) \\ = - 36{x}^{3} {y}^{2} + 36x^{2} {y}^{3} + 6 {x}^{3}$

I hope I helped you^_^

4 0

2 years ago

The vertex of this parabola is at (-4, -1). When the y-value is 0, the x-value is 2. What is the coefficient of the squared term

satela [25.4K]

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
y=a(x-(-4))^2-1\implies y=a(x+4)^2-1
\\\\\\
\textit{now, we also know that }
\begin{cases}
y=0\\
x=2
\end{cases}\implies \underline{0}=a(\underline{2}+4)^2-1$

solve for "a"

5 0

2 years ago