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Dennis_Churaev [7]
3 years ago
6

Determine the coordinates for the intersection of the diagonals in RSTU with vertices at R(-8,-2),S(-6,7), T(6,7) and U(4,-2)

Mathematics
2 answers:
irina [24]3 years ago
6 0
It is answer choice A. (-1, 2.5)
Kamila [148]3 years ago
6 0

Answer:

A. (-1,2.5)

Step-by-step explanation:

We have been the coordinates of a an quadrilateral RSTU with vertices at R(-8,-2),S(-6,7), T(6,7) and U(4,-2). We are asked to find the coordinates for the intersection of the diagonals of RSTU.

First of let us draw the quadrilateral on coordinate plane.

Please find the attachment for the quadrilateral.

We can see that our given quadrilateral is a parallelogram. Now let us draw diagonals of our parallelogram.

We can see that both diagonals are intersecting at point (-1,2.5), therefore, option A is the correct choice.  

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three trigonometric functions for a given angle are shown below csc theta = 13/12, sec theta = -13/5, cot theta = -5/12 what are
goldenfox [79]
We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12

we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13

sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13

sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant

therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12

the answer is
point (-5,12)

see the attached figure

6 0
3 years ago
Read 2 more answers
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
2 years ago
The area of a square piece of cardboard is 81 square inches. What is the length of the cardboard
vredina [299]
9 because the square root of 81 is 9
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If I run 6 miles per hour. How fast do I run in km per minute?
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9.66 - you just multiple 6 by 1.61
7 0
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I need some help plz!!!
jek_recluse [69]
1.04 kilograms

1 gram = .001 kilogram
2x520= 1040
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5 0
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