Determine the coordinates for the intersection of the diagonals in RSTU with vertices at R(-8,-2),S(-6,7), T(6,7) and U(4,-2)
2 answers:
Answer:
A. (-1,2.5)
Step-by-step explanation:
We have been the coordinates of a an quadrilateral RSTU with vertices at R(-8,-2),S(-6,7), T(6,7) and U(4,-2). We are asked to find the coordinates for the intersection of the diagonals of RSTU.
First of let us draw the quadrilateral on coordinate plane.
Please find the attachment for the quadrilateral.
We can see that our given quadrilateral is a parallelogram. Now let us draw diagonals of our parallelogram.
We can see that both diagonals are intersecting at point (-1,2.5), therefore, option A is the correct choice.
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Answer:
A) y^3+27
Step-by-step explanation:
There are two ways of solving this problem:
1. Recognizing this as the factored form of the sum of perfect cubes
2. Distribute and add the like terms.
1. In order to distribute we must multiply y by y^2-3y+9, and then 3 by y^2-3y+9:
After we add the positive and negative 3y^2 and 9y, they will cancel out and be gone entirely:
2. You know how you can factor the difference of perfect squares?
As an example:
Well, not many people know this but you can actually factor both the sum and difference of perfect cubes:
Because we have these identities, we can easily establish here that we have the sum of perfect cubes, and that (y+3)(y^2-3y+9)= y^3+3^3 = y^3+27