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Dennis_Churaev [7]
3 years ago
6

Determine the coordinates for the intersection of the diagonals in RSTU with vertices at R(-8,-2),S(-6,7), T(6,7) and U(4,-2)

Mathematics
2 answers:
irina [24]3 years ago
6 0
It is answer choice A. (-1, 2.5)
Kamila [148]3 years ago
6 0

Answer:

A. (-1,2.5)

Step-by-step explanation:

We have been the coordinates of a an quadrilateral RSTU with vertices at R(-8,-2),S(-6,7), T(6,7) and U(4,-2). We are asked to find the coordinates for the intersection of the diagonals of RSTU.

First of let us draw the quadrilateral on coordinate plane.

Please find the attachment for the quadrilateral.

We can see that our given quadrilateral is a parallelogram. Now let us draw diagonals of our parallelogram.

We can see that both diagonals are intersecting at point (-1,2.5), therefore, option A is the correct choice.  

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Name the correct angles 5 and 7
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Answer:

Acute angle.

Right angle.

Obtuse angle.

Straight angle.

Reflex angle

Step-by-step explanation:

4 0
3 years ago
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HELPPPP please !!!!!,!!?
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Mercury has the greater density than that of Venus .

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4 years ago
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Radius of a coin is 3cm then calculate its surface area
dexar [7]
This is your perfect answer

4 0
3 years ago
What is the sum? StartFraction 3 Over x squared minus 9 EndFraction StartFraction 5 Over x 3 EndFraction.
V125BC [204]

The sum of the two fractional number, which consist in the variable <em>x</em> is in the polynomial function,

f(x)=\dfrac{5x-12}{(x+3)(x-3)}

<h3>What is the sum of fraction number?</h3>

Fraction number is the number which is a part of a whole number. It is written with a numerator and denominator.

Fraction number are written as,

\dfrac{a}{b}

Here (a) is the numerator and (b) is the denominator.

To find the sum of two fraction numbers, cross multiply both the numbers or find the least common factor as denominator.

The first fraction number given in the problem is,

\dfrac{3}{x^2+9}

The second fraction number given in the problem is,

\dfrac{5}{x+3}

Let the sum of these number is f(x). Thus,

f(x)=\dfrac{3}{x^2-9}+\dfrac{5}{x+3}\\f(x)=\dfrac{3}{(x+3)(x-3)}+\dfrac{5}{x+3}\\

Solve it further as,

f(x)=\dfrac{3+5(x-3)}{(x+3)(x-3)}\\f(x)=\dfrac{3+5x-15}{(x+3)(x-3)}\\f(x)=\dfrac{5x-12}{(x+3)(x-3)}

Thus, the sum of the two fractional number is,

f(x)=\dfrac{5x-12}{(x+3)(x-3)}

Learn more about the fraction number here:

brainly.com/question/78672

6 0
2 years ago
the length of a rectangle is 4 cm more than the width and the perimeter is at least 48cm. what are the smallest possible dimensi
wel
X=length
x+4=width
2(x+4)+2x=48
2x+8+2x=48
4x=40
x=10
It means that length will be equal 10 and width 14 :)
so dimensions of this rectangle is 10x14 :)
8 0
3 years ago
Read 2 more answers
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