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Pie
3 years ago
12

Find the equation of the line through the points (-3,-3) and (2,-1) using point-slope form. Then rewrite the

Mathematics
1 answer:
IrinaVladis [17]3 years ago
3 0

Answer: See below

Step-by-step explanation:

The point-slope equation is y-y₁=m(x-x₁). Since we don't know our slope, we can use the formula m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  } to find the slope. All we have to do is use the coordinate we were given and plug it into the formula.

m=\frac{-1-(-3)}{2-(-3)} =\frac{2}{5}

Now that we have the slope, we can fill out the point-slope equation.

y-(-3)=2/5(x-(-3))

y+6=2/5(x+3)

This is the point-slope form.

Now, we can distribute and solve to get slope-intercept form.

y+6=2/5x+6/5

y=2/5x-24/5

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Answer:

The solution is x =0.

Step-by-step explanation:

The equation

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and can be further simplified to

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Now, taking the inverse sine of both sides we get:

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The value of the right side on the interval [0,2\pi) is

sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o) ,

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conditional statement: p → q

inverse: ~p → ~q (the symbol ~ means the negation)

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conditional statement: p → q

converse: q → p

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