All categories

2 years ago

A pound of rice crackers costs $2.88. Matthew purchased 1/4 pound of crackers. How much did he pay for the crackers.

Mathematics

2 answers:

Slav-nsk [51]2 years ago

8 0

2.88/4=0.72
So he payed $0.72 for the crackers

dlinn [17]2 years ago

7 0

So you know that a pound of rice crackers cost $2.88. You also know that Matthew bought 1/4 or 25% or 0.25 of a pound. This means that by multiplying 0.25 by $2.88, you can determine the cost.

0.25 x 2.88 = $0.72
Therefore, Matthew paid 72 cents or $0.72 for 1/4 pound of rice crackers

You might be interested in

Answer this volume based Question. I will make uh brainliest + 50 points

Harlamova29_29 [7]

Answer:

$\huge{\purple {r= 2\times\sqrt[3]3}}$

$\huge 2\times \sqrt [3]3 = 2.88$

Step-by-step explanation:

For solid iron sphere:
radius (r) = 2 cm (Given)

Formula for $V_{sphere}$ is given as:

$V_{sphere} =\frac{4}{3}\pi r^3$

$\implies V_{sphere} =\frac{4}{3}\pi (2)^3$

$\implies V_{sphere} =\frac{32}{3}\pi \:cm^3$

For cone:
r : h = 3 : 4 (Given)
Let r = 3x & h = 4x

Formula for $V_{cone}$ is given as:

$V_{cone} =\frac{1}{3}\pi r^2h$

$\implies V_{cone} =\frac{1}{3}\pi (3x)^2(4x)$

$\implies V_{cone} =\frac{1}{3}\pi (36x^3)$

$\implies V_{cone} =12\pi x^3\: cm^3$

It is given that: iron sphere is melted and recasted in a solid right circular cone of same volume
$\implies V_{cone} = V_{sphere}$

$\implies 12\cancel{\pi} x^3= \frac{32}{3}\cancel{\pi}$

$\implies 12x^3= \frac{32}{3}$

$\implies x^3= \frac{32}{36}$

$\implies x^3= \frac{8}{9}$

$\implies x= \sqrt[3]{\frac{8}{3^2}}$

$\implies x={\frac{2}{ \sqrt[3]{3^2}}}$

$\because r = 3x$

$\implies r=3\times {\frac{2}{ \sqrt[3]{3^2}}}$

$\implies r=3\times 2(3)^{-\frac{2}{3}}$

$\implies r= 2\times (3)^{1-\frac{2}{3}}$

$\implies r= 2\times (3)^{\frac{1}{3}}$

$\implies \huge{\purple {r= 2\times\sqrt[3]3}}$
Assuming log on both sides, we find:

$log r = log (2\times \sqrt [3]3)$

$log r = log (2\times 3^{\frac{1}{3}})$

$log r = log 2+ log 3^{\frac{1}{3}}$

$log r = log 2+ \frac{1}{3}log 3$

$log r = 0.4600704139$

Taking antilog on both sides, we find:

$antilog(log r )= antilog(0.4600704139)$

$\implies r = 2.8844991406$

$\implies \huge \red{r = 2.88\: cm}$

$\implies 2\times \sqrt [3]3 = 2.88$

8 0

1 year ago

PLEASE HELP ASAP WILL MEDAL BRAINLIEST

Naddik [55]

Given
Present investment, P = 22000
APR, r = 0.0525
compounding time = 10 years
Future amount, A

A. compounded annually
n=10*1=10
i=r=0.0525
A=P(1+i)^n
=22000(1+0.0525)^10
=36698.11

B. compounded quarterly
n=10*4=40
i=r/4=0.0525/4
A=P(1+i)^n
=22000*(1+0.0525/4)^40
=37063.29

Therefore, by compounding quarterly, she will get, at the end of 10 years investment, an additional amount of
37063.29-36698.11
=$365.18

5 0

2 years ago

A patient is given a 50 mg dose of medicine. The medicine's effectiveness decreases every hour at a constant rate of

WITCHER [35]

Answer:

f(x) = 50(0.60)x; 18 mg

3 0

2 years ago

Read 2 more answers

What is the length of side s of the square shown below?

AnnZ [28]

Answer:

Step-by-step explanation:

Using the properties of 45-45-90 triangles

8=x*sqrt(2)

4sqrt(2)=x

6 0

2 years ago

Mentalmath grade 3 $1.00-$0.37

Mkey [24]

Answer:

$0.63

Step-by-step explanation:

6 0

2 years ago