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Nastasia [14]
1 year ago
14

The correlation coefficient r between the values assumed by two variables, X

Mathematics
1 answer:
Flura [38]1 year ago
4 0

The slope of the line of best fit to the raw-score scatter plot is 0.98

  • The equation is y = 0.98x - 3.74
  • The value of y given that x = 12 is 8.02

<h3>How to determine the slope of the line?</h3>

From the question, we have the following parameters that can be used in our computation:

  • Standard deviations of X, Sx = 1.88
  • Standard deviations of Y, Sy =2.45
  • Correlation coefficient, r between X and Y = 0.75

The slope (b) of the line is calculated as

b = r * Sy/Sx

Substitute the known values in the above equation, so, we have the following representation

b = 0.75 * 2.45/1.88

Evaluate

b = 0.98

<h3>The equation of the line of best fit</h3>

A linear equation is represented as

y = bx + c

Where

Slope = b

y-intercept = c

In (a), we have

b = 0.98

So, we have

y = 0.98x + c

Recall that the point (13, 9) is on the line of best fit.

So, we have

9 = 0.98 * 13 + c

This gives

9 = 12.74 + c

Evaluate

c = -3.74

So, we have

y = 0.98x - 3.74

<h3>The value of y from x</h3>

Here, we have

x = 12

So, we have

y = 0.98 x 12 - 3.74

Evaluate

y = 8.02

Read more about line of best fit at

brainly.com/question/1564293

#SPJ1

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\large\bf{\underline{Answer:}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{ = 3000 \:ft^2}

__________________________________________

\large\bf{\underline{Given:}}

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  • And 2 triangles with base =30 ft and height = 20 ft

\large\bf{\underline{To\: find:}}

  • Total surface area of figure

\large\bf{\underline{Therefore:}}

\bf{area \:of\: figure}

‎ㅤ{\bf = area \:of \:3\: rectangles + 2 \: triangles}

\large\bf{\underline{Formulas:}}

\boxed{\bf\pink{area\:of\: triangle= \frac{1}{2}\times base\times height}}

\boxed{\bf\pink{area\:of\: rectangle=length\times breadth}}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3\times (28 \times 25 )+ 2(\frac{1}{2} \times 30 \times 20)}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3 \times 800 + 2 \times 300}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{=2400+ 600}

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\large\bf{= 3000}

__________________________________________

\large\bf{\underline{Hence,}}

❒ Area of given figure

‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎‎‎ ‎ ‎\huge\mathfrak{= 3000\: ft^2}

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