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Alex_Xolod [135]
3 years ago
6

Help (evaluate the function)​

Mathematics
1 answer:
AveGali [126]3 years ago
6 0

Answer:

16

Step-by-step explanation:

Replace the variable in the expression

f (-2) = (-2)^2-10 x -2

f  ( − 2 ) = − 4 + 20

Add  − 4  and  20

f  ( − 2 ) = 16

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What is the value of n?
faltersainse [42]

Answer:

  69

Step-by-step explanation:

The sum of exterior angles is 360°, so ...

  n° +131° +160° = 360°

  n° = 360° -291° = 69°

  n = 69

7 0
3 years ago
PLEASE HELP ASAP I’LL GIVE BRAINLEST ITS ALEKS ALGEBRA 2 MATH
vlada-n [284]
A)
145 - 5d
5d = 145, set equal

29 days to lay all the track

b)
5*19 = 95

145-95 = 50

After 19 days, they have 50 miles to go.
4 0
2 years ago
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Solve any evens for 20 points apiece
Vlad1618 [11]
? what do you mean. do you have questions that need to be solved?
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3 years ago
What is the volume of the water contained in the cylinder?
Margarita [4]

Answer:

Vf = 118.365 m3

Step-by-step explanation:

Vcil = Pi*[(20)^2]*(100=

Vcil = 125.600 m3

Vesf = (4/3)*Pi*(12)^3

Vesf = 7235 m3

Then

Vf = Vci - Vesf

Vf = 125.600 - 7235

Vf = 118365 m3

Best regards

3 0
3 years ago
The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

                   = 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0
3 years ago
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