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You multiply fractions simply by multiplying numerators and denominators with each other:

Answer:
y=ln(x/(1-x))
Step-by-step explanation:
y=e^x/(1+e^x)
Cross multiply
y(1+e^x)=e^x
Distribute
y+ye^x=e^x
Put anything with x on with side and everything without x on opposing side:
y=e^x-ye^x
Factor right hand side
y=(1-y)e^x
Divide both sides by (1-y)
y/(1-y)=e^x
Use natural log.
ln(y/(1-y))=x
The inverse is
y=ln(x/(1-x))
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With the help of the given equation, we know that the automobile is worth $12528.15 after four years.
<h3>
What are equations?</h3>
- A mathematical equation is a formula that uses the equals sign to represent the equality of two expressions.
- a formula that expresses the connection between two expressions on each side of a sign.
- Typically, it has a single variable and an equal sign.
- Like this: 2x - 4 Equals 2.
- In the above example, the variable x exists.
So, the equation of depreciation: y = A(1 - r)∧t
The current value is y.
A is the initial cost.
r is the depreciation rate.
t is the time in years, and
In four years, we must ascertain the present value.
Now,
y = $24000(1 - 0.15)⁴
y = 24000(0.85)⁴
y = 24000 × 0.52200625
y = 12528.15
Therefore, with the help of the given equation, we know that the automobile is worth $12528.15 after four years.
Know more about equations here:
brainly.com/question/28937794
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Complete question:
The general equation for depreciation is given by y = A(1 – r)t, where y = current value, A = original cost, r = rate of depreciation, and t = time, in years. The original value of a car is $24,000. It depreciates 15% annually. What is its value in 4 years? $