3 years ago

PLEASE HELPPPP!!!!! need help with this

Mathematics

1 answer:

Daniel [21]3 years ago

7 0

Answer:

-2

Step-by-step explanation:

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An object at the top of a building with height 110 feet is thrown upward with an initial speed of 23 ft/s. Find its position z(t

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Answer:

Step-by-step explanation:

Given

Height of building is $h=110\ ft$

Initial upward velocity $u=23\ ft/s$

height of object is given by

$z(t)=ut+\frac{1}{2}gt^2$

but building is already at a height of 110 ft so z(t) must be given by

$Z(t)=ut+\frac{1}{2}(-g)t^2+110$

$Z(t)=23\times t-\frac{1}{2}\times 9.8\times t^2$

$Z(t)=-16t^2+23t+110$

Time when it hits is given by when Z(t)=0[/tex]

$-16t^2+23t+110=0$

$t=\frac{-23\pm \sqrt{(23)^2-4\times (-16)\times 110}}{2\times (-16)}$

$t=\frac{-23\pm 87}{-32}$

$t=3.43\ s$

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45.Erica Glaser deposits a check for $20,005.00 and $1.234.00 in cash. What is het total

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The product of 5 and the cube of a number increased by the difference of 6 and x

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Answer:

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Step-by-step explanation:

given the information provided, this is the equation you're looking for

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I need help ASAP <br>If ANYONE gets it right will be given <br>BRAINLIEST!!!

kifflom [539]

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It's actually pretty basic

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