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aleksklad [387]
3 years ago
9

Solve the system of equations below algebraically 2x+3y=6 and -5x+2y=4

Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0


Steps
I’m using elimination so I’m trying to get rid of y
To do that I multiply the first equation by 2 and the second by -3. Then solve
4x + 6x = 12
15x + -6x = -12
—————————
19x + 0 = 0
Divid by 19 to get x to one side. 0/19 is 0 so
X= 0
Plug that into an equation so 0 + 3y = 6
Divid by 3 and y = 2
Answer x = 0 y = 2
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Answer:

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Step-by-step explanation:

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Then

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Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

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We want to test if the true mean is higher than 5, the system of hypothesis are :  

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The degrees of freedom first given by:  

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Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

t_{\alpha}= 1.796

And for this case the rejection region would be:

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