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2 years ago

Please help the above following questions asap. Thanks A Lot !!! :)

Mathematics

2 answers:

tester [92]2 years ago

7 0

Question (a):
cos(45°) = adjacent/hypotenuse
adjacent = hypotenuse × cos(45°)
adjacent = 7 × cos(45°)
adjacent = 4.9497474683
==> The foot of the ladder is 4.95m from the wall.

laila [671]2 years ago

6 0

Since both are right triangles you can use the Pythagorean Theorem.

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Math question please show work for brainliest :)

yKpoI14uk [10]

Hello!
First of all you look at how many X's the line moves by, in this case it is -3

Then you look at how many y's the line moves by, in this case it is -2

Then you add together the number of X's moved and the number of y's moved:
-3x + -2y
( adding a negative number is the same as subtracting that number)
thus the answer is A. -3x-2y

Hope This helps! :)

5 0

2 years ago

The measure of one acute angle in this right triangle is 45°.

maks197457 [2]

Answer:

45°

Step-by-step explanation:

90-45=45°

3 0

2 years ago

Read 2 more answers

Ana drew a map of the Panama Canal. In the scale Ana used for the map, 4 centimeters represents 20 kilometers. The actual length

yawa3891 [41]

Answer:

Length of the canal on the map is 16.4 centimeters.

Step-by-step explanation:

If actual length of Panama Canal = 20 kilometers

and length of the canal on map = 4 centimeters

Then scale factor = $\frac{\text{Length of canal on map}}{\text{Actual length of canal}}$

= $\frac{4}{20}$

= $\frac{1}{5}$

If the actual length of Panama Canal = 82 kilometers

Then the length of canal on the map = Actual length × Scale factor

= $82\times \frac{1}{5}$

= 16.4 centimeters

Therefore, length of the canal on the map is 16.4 centimeters.

4 0

3 years ago

Plz help!! Will give 30 points!!

Inessa [10]

Answer:

B) 12

Step-by-step explanation:

C is the circumference, d is the diameter, and r is the radius. They are related by the following equations:

d = 2r

C = πd = 2πr

If d = 6.0, then r = 3.0.

If C / C' = 0.25, then:

(2πr) / (2πr') = 0.25

r / r' = 0.25

3 / r' = 0.25

r' = 12

8 0

3 years ago

Read 2 more answers

Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0

Masja [62]

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

$h(x)=\dfrac{1}{3}|x-6|+4$

Put the values of x to the equation of the function h(x):

$x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6$

6 0

2 years ago