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3 years ago

I need help finding x

Mathematics

1 answer:

natulia [17]3 years ago

7 0

To find x u might wanna add up all the numbers and divide the answer by the sides the shape has :) hope this helps

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Please help. I will give five stars and 10 points for correct answer with explanation.

anygoal [31]

Answer:

A: It has no solution

Step-by-step explanation:

1. 3/4z - 1/4z + 3 = 2/4z + 5

2. 2/4z +3 = 2/4z + 5

3. 3 = 5 (No solution because 3 can never be equal to 5)

7 0

3 years ago

The route to an ancient pyramid is 79 miles long

Elanso [62]

If the speed is 26.33 miles per day. Then the number of miles you traveled on the 4 days will be 105.33 miles.

<h3>What is speed?</h3>

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

Speed = Distance/Time

The route to an ancient pyramid is 79 miles long.

If you traveled the same amount of time for 3 days.

Then the speed will be

S = 79 / 3

S = 26.33 miles per day

Then the number of miles you traveled on the 4 day will be

26.33 = D / 4

D = 105.33 miles

More about the speed link is given below.

brainly.com/question/7359669

#SPJ1

5 0

2 years ago

Please help me with this now!!!please!!

Alja [10]

Answer:

Step-by-step explanation:

4 0

3 years ago

Use the substitution u = tan(x) to evaluate the following. int_0^(pi/6) (text(tan) ^2 x text( sec) ^4 x) text( ) dx

Rudiy27

If we use the substitution $u = \tan x$ , then $du = \sec^2 {x}\ dx$ . If you try substituting just $u$ and $du$ into the integrand, though, you'll notice that there's a $\sec^2x$ left over that we have to deal with.

To get rid of this problem, use the identity $\tan^2 x + 1 = \sec^2 x$ and substitute in the left side of the identity for the extra $\sec^2x$ , as shown:

$\int\limits^{\pi/6}_0 {tan^2 x \ sec^4 x} \, dx$
$\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx$

From there, we can substitute in $u$ and $du$ , and then evaluate:

$\int\limits^{\pi/6}_0 {tan^2 x \ (tan^2 x + 1) \ sec^2 x} \, dx$
$\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^2(u^2 + 1)} \, du$
$\int\limits^{\frac{1}{\sqrt{3}}}_0 {u^4 + u^2} \, du$
$= \left.\frac{u^5}{5} + \frac{u^3}{3}\right|_0^\frac{1}{\sqrt{3}}$
$= (\frac{(\frac{1}{\sqrt{3}})^5}{5} + \frac{(\frac{1}{\sqrt{3}})^3}{3}) - (\frac{(0)^5}{5} + \frac{(0)^3}{3})$
$= \frac{1}{45\sqrt{3}} + \frac{1}{9\sqrt{3}} = \frac{6}{45\sqrt{3}} = \bf \frac{2}{15\sqrt{3}}$

8 0

3 years ago

Are metals and non-metals good conductors true or false

andre [41]

False only metals are good conductors

3 0

3 years ago

Read 2 more answers