Answer:
Option D
Step-by-step explanation:
We need the product of:
(-3s + 2t)*(4s - t)
We can use the distributive property:
(a + b)*(c + d) = a*c +b*c + a*d + b*d
Applying to our case:
(-3s + 2t)*(4s - t) = (-3s)*4s + (-3s)*(-t) + 2t*4s + (2t)*(-t)
(-3s + 2t)*(4s - t) = -12(s^2) + 3st + 8ts - 2(t^2)
(-3s + 2t)*(4s - t) = -12(s^2) + 11ts - 2(t^2)
So, the correct is option D negative 12 s squared + 11 s t minus 2 t squared
(6+18)^2 = m^2 + m^2
=> 2m^2 = (24)^2
=> m = 24/sqrt(2)
Answer:
At any given moment, the red ant's coordinates may be written as (a, a) where a > 0. The red ant's distance from the anthill is
. The black ant's coordinates may be written as (-a, -a) and the black ant's distance from the anthill is
. This shows that at any given moment, both ants are
units from the anthill.
Step-by-step explanation:
Given:
red ant's coordinates written as (a,a)
black ant's coordinates are written as (-a, -a)
To find:
The distance of red and black ants from anthill
Solution:
Compute the distance of red ant from the anthill using distance formula
d (red ant) = 
= 
= 
=
So distance of red ant from anthill is
Compute the distance of black ant from the anthill using distance formula
d (black ant) = 
= 
= 
= 
=
So distance of black ant from anthill is
Hence both ants are
units from the anthill.
230,344,996 is in number form
Use this formula and I can't answer because you do not tell me which one is the height.