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3 years ago

There is a mistake in this problem find the mistake

Mathematics

1 answer:

fiasKO [112]3 years ago

8 0

Answer:

The mistake is the problem itself. It should be

5x=100

x=100÷5

x=20

Step-by-step explanation:

The mistake is the problem itself. It should be

5x=100

x=100÷5

x=20

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I need help with these ASAP thanks

Nataly_w [17]

Answer:

a. $y=\frac{2x}{x-5}$

b. $y=\frac{2-4x}{x-3}$

Step-by-step explanation:

change switch x and y and then solve for y.

a. $x=\frac{5y}{y-2}$

$x(y-2)=5y$

$xy-2x=5y$

$xy-5y=2x$

$y(x-5)=2x$

$y=\frac{2x}{x-5}$

same for b.

b. $x=\frac{3y+2}{y+4}$

$x(y+4)=3y+2$

$xy+4x=3y+2$

$xy-3y=2-4x$

$y(x-3)=2-4x$

$y=\frac{2-4x}{x-3}$

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3 years ago

What is log39 = x in exponential form?

rodikova [14]

Answer:

9 = $3^{x}$

Step-by-step explanation:

Using the rule of logarithms

$log_{b}$ x = n ⇔ x = $b^{n}$

Given

$log_{3}$ 9 = x ⇔ 9 = $3^{x}$ ← in exponential form

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3 years ago

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Devon babysits x hours a week after school for 5$ an hour, and also has a job as a cashier y hours a week for $10 an hour. He wa

Papessa [141]

Answer:

The inequality expression are $5x + 10y\geq\$70 \ and \ x + y \leq 10 hours$

Step-by-step explanation:

Given:

Number of hours for babysitting for a week = $x \ hours$

Charge for baby sitting = 5$ an hour

Money earned for babysitting in x hours = $5x$

Number of hours for cashier for a week = $y \ hours$

Charge for Cashier = $10 an hour

Money earned for Cashier in y hours = $10y$

He wants to earn at least 70$.

Hence the expression becomes.

$5x + 10y \geq 70 \$$

Also,

He can’t work any more than 10 hours a week

Hence the expression becomes.

$x + y < 10 \ hours$

Inequality equation for the given statements are:

The inequality expression are $5x + 10y\geq\$70 \ and \ x + y \leq 10 hours$

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4 years ago

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Answer:

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