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Rainbow [258]
4 years ago
5

Find the product. 8y^3(-3y^2) __ Y----

Mathematics
1 answer:
ivanzaharov [21]4 years ago
3 0

Answer:

y= 12

Step-by-step explanation:

8y x 3(-3y x 2)

By multiplying 3 inside the bracket values

= 8y x -9y x 6

By multiplying the same polynomials co-coefficients

= -72y x 6

y x 6 =72

By Shifting the negative term to the other side

y = 72/6

By dividing

y= 12

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Talia tossed a penny many times. She got 20 heads and 80 tails. She said the experimental probability of getting heads was 20 80
iragen [17]

Answer:

the experimental probability is 1/5

Step-by-step explanation:

This is because one to calculate the experimental probability one has to divide the favorable events over the possible events, and those that Talia did were the favorable events divided the non-favorable events

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5 0
3 years ago
The table shows the hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale. Grade 7 Grade 8 20 21 15
Naddika [18.5K]

Answer:

1. The interquartile range for the grade 7 data is 6.

2. The interquartile range for the grade 8 data is 6.

3. The difference of the medians of the two data sets is 2.

4. The difference is about 1/3 times the interquartile range of either data set.

Step-by-step explanation:

The hourly cookie sales by students in grades 7 and 8 at the school's annual bake sale is given by the following table.

Grade 7       Grade 8

  20                  21

  15                  29

  30                  14

  24                  19

   18           24

   21                 25

The data set for grade 7 is

20, 15, 30, 24, 18, 21

Arrange the data in ascending order.

15, 18, 20, 21, 24, 30

Divide the data in four equal parts.

(15), 18, (20), (21), 24,( 30)

Q_1=18, Median=\frac{20+21}{2}=20.5, Q_3=24

The interquartile range for the grade 7 data is

IQR=Q_3-Q_1=24-18=6

Therefore the interquartile range for the grade 7 data is 6.

The data set for grade 8 is

21, 29, 14, 19, 24, 25

Arrange the data in ascending order.

14, 19, 21, 24, 25, 29

Divide the data in four equal parts.

(14), 19, (21), (24), 25, (29)

Q_1=19, Median=\frac{21+24}{2}=22.5, Q_3=25

The interquartile range for the grade 8 data is

IQR=Q_3-Q_1=25-19=6

Therefore the interquartile range for the grade 8 data is 6.

The difference of the medians of the two data sets is

D=22.5-20.5=2

Therefore the difference of the medians of the two data sets is 2.

Let the difference is about x times the interquartile range of either data set.

The IQR of each data is 6.

D=x(IQR)

2=x(6)

\frac{2}{6}=x

\frac{1}{3}=x

Therefore the difference is about 1/3 times the interquartile range of either data set.

8 0
3 years ago
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