Even integer: 2 x a, where a is a natural number without 0;
Odd integer : 2 x b + 1 , where b is a natural number;
So, 2 x a + 2 x b+ 1 = 2 x ( a + b ) + 1, which is an odd integer.
Answer:
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Step-by-step explanation:
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Answer:
SOLUTION #1
If the digits are allowed to repeat, the answer is 27. (There are three ways to fill digit 1, three ways to fill digit 2, and three ways to fill digit 3. Therefore, there are 3 x 3 x 3 = 27 possibilities.)
SOLUTION #2
If the digits are NOT allowed to repeat, the answer is 6. (There are three ways to fill digit 1, only two ways to fill digit 2, and only one way to fill digit 3. Therefore, there are 3 x 2 x 1 = 6 possibilities.)
Step-by-step explanation:
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Look at the graph below carefully
Observe the results of shifting ={2}^{x}f(x)=2x
vertically:
The domain, (−∞,∞) remains unchanged.
When the function is shifted up 3 units to ={2}^{x}+3g(x)=2x +3:
The y-intercept shifts up 3 units to (0,4).
The asymptote shifts up 3 units to y=3y=3.
The range becomes (3,∞).
When the function is shifted down 3 units to ={2}^{x}-3h(x)=2 x −3:
The y-intercept shifts down 3 units to (0,−2).
The asymptote also shifts down 3 units to y=-3y=−3.
The range becomes (−3,∞).
