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Alona [7]
3 years ago
7

During flu season, there were 124 students out of school on a particular day. If there are 775 students in the school, what perc

ent
of them have the flu
Mathematics
1 answer:
vitfil [10]3 years ago
8 0

Answ

Step-by-step explanation:

soln,

total number of students =775

present students=124

now,

let the % of students who have flu be x%

here,

x% of 775 is 124

x/100*775=124

775x=12400

x=12400/775

x=16%

So, the% of students is 16%.

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Which statment descirbes the soloution to a equation<br> a+5(2a-1)+3=11a-2
Andreyy89

Answer:

Any real number.

Step-by-step explanation:

I dunno what you're asking, but Im assuming you need what a equals to.

a+5(2a-1)+3=11a-2\\a+10a-5+3=11a-2\\11a-2=11a-2\\

The answer is any real number.

7 0
3 years ago
Metal Fabrication If an open box is made from a tin sheet 10 in. square by cutting out identical squares from each corner and be
MrRa [10]

Answer:

  • ength (l) : (10-2*5/3) = 20/3
  • width(w): (10 - 2*5/3) = 20/3
  • height(h): 5/3

Step-by-step explanation:

Let x is the side of identical squares

By cutting out identical squares from each corner and bending up the resulting flaps, the dimension are:

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  • width(w): (10-2x)
  • height(h): x

The volume will be:

V = (10-2x) (10-2x) x

<=> V = (10x-2x^{2}) (10-2x)

<=> V = 100x -20x^{2} - 20x^{2} + 4x^{3}

<=> V = 4x^{3}  - 40x^{2} + 100x

To determine the dimensions of the largest box that can be made, we need to use the derivative and and set it to zero for the maximum volume

dV/dx = 12x^{2} -80x + 100

<=>  12x^{2} -80x + 100 =0

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=>

  • length (l) : (10-2*5/3) = 20/3
  • width(w): (10 - 2*5/3) = 20/3
  • height(h): 5/3
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3 years ago
How would you solve this?
tangare [24]

Answer:

The area of the black square is equal to the sum of the areas of the gray squares.

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UkoKoshka [18]

Answer:

0.229

Step-by-step explanation:

Given that the difference between the two sample means follows anormal distribution with a mean of11.00 and standard deviation equal to1.4387

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3 0
3 years ago
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