Help me out please?

Given below are descriptions of two lines.

gulaghasi [49]

Answer:

Line 1 is 1/3

Line 2 is 1/3 as well

Choice 1

Step-by-step explanation:

Rise over run

Line 1:

$\frac{(7)-(3)}{(6)-(-6)}$

$\frac{4}{12}$

Simplify:

1/3

Line 2:

$\frac{(2)-(1)}{(-3)-(-6)}$

$\frac{1}{3}$

1/3

1 is Paralell to 2 because they have the same slope

I hope this helps! :D

Pls give thx and brainliest if i’m right!

5 0

2 years ago

For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?

Bond [772]

Given that $r=\theta$ , then $r'=1$

The slope of a tangent line in the polar coordinate is given by:

$m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}$

Thus, we have:

$m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}$

Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

$\sin\theta+\theta\cos\theta=0 \\ \\ \theta\cos\theta=-\sin\theta \\ \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta$

Therefore, the values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

θ = 0

θ = 2.02875783811043

θ = 4.91318043943488

Part B:

For vertical tangent lines, $\frac{1}{m} =0$

Thus, we have:

$\cos\theta-\theta\sin\theta=0 \\ \\ \Rightarrow\theta\sin\theta=\cos\theta \\ \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta$

Therefore, the values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

θ = 4.91718592528713

3 0

2 years ago

Two welders worked a total of 46 h on a project. One welder made $34/h, while the other made $39/h. If the gross earnings of the

Ratling [72]

Answer:

25 and 21 hours respectively

Step-by-step explanation:

Let the number of hours worked by each welder be x and y respectively.

They worked a total of 46 hours. This means :

x + y = 46 hours.......(I)

Now, given their hourly charges, since we have the total amount of money realized, we can make an equation out of it. This means:

34x + 39y = 1669........(ii)

We then solve both simultaneously. From I, x = 46 -y

We can substitute this into ii

34(46 -y) + 39y = 1669

1564 -34y + 39y = 1669

5y = 1669 - 1564

5y = 105

y = 105/5 = 21

x = 46 - y

x = 46 - 21 = 25 hours

The numbers of hours worked by the welders are 25 and 21 respectively

4 0

2 years ago

a group of friends shared 3 rolls of clay equally. if each student gor 1/2 of a roll of clay, how many students were in the grou

klemol [59]

6 students – 3 rolls of clay divided by each portion given to a student (0.5) equals 6, meaning only six students where able to receive some clay

8 0

2 years ago

I JUST NEED AN ANSWER PLEASE

irga5000 [103]

Answer: 1/3

Step-by-step explanation:

lol hope i helped:)

3 0

1 year ago