This is an incomplete question, here is a complete question.
Consider the second-order decomposition of nitroysl chloride:
At 450 K the rate constant is 15.4 atm⁻¹s⁻¹. How much time (in s) is needed for NOCl originally at a partial pressure of 53 torr to decay to 10.6 torr?
Answer : The time needed for NOCl is, 2.52 seconds.
Explanation : Given,
Rate constant =
Initial partial pressure of NOCl = 56 torr = 0.0737 atm
final partial pressure of NOCl = 14.5 torr = 0.0191 atm
The expression used for second order kinetics is:
where,
k = rate constant
t = time
= concentration at time 't'
= initial concentration
As we know that,
Thus, the expression of second order kinetics will be:
As,
So, ............(1)
Now put all the given values in the above expression 1, we get:
Therefore, the time needed for NOCl is, 2.52 seconds.
Answer:
189.75g
Explanation:
mass is equal to mole*molar mass and the molar Mass of KNO3 is 55 so 3.45*55 is equal to 189.75
Pretty sure it’s C but if it’s not I’m sorry
The glow is created by electrons emitted in radioactive decays in the radioactive core. Radioactivity is the release of energy from the decay of the nuclei of certain kinds of atoms and isotopes. Atomic nuclei consist of protons and neutrons bound together in tiny bundles at the center of atoms.
i hope this help :)
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