Answer:
The true statements are given below.
Explanation:
1 D glucose is a reducing sugar
2 The oxidation of reducing sugar forms a carboxylic acid sugar.
D glucose is a reducing sugar because glucose contain a free hydroxyl group (-OH)in its anomeric carbon.
The oxidation of reducing sugar result in the conversion of -CHO group in case of aldose sugar and -CH2OH group in case of ketose sugar into carboxylic acid(-COOH).
Answer:
Explanation:
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In this case, for such formation of sulfur hexafluoride, the standard enthalpy of formation is -1220.47 kJ/mol (data extracted from NIST database). Next, we compute the moles in 10.0 grams of sulfur hexafluoride as shown below:
Next, for the given energy, we compute the total heat that is liberated:
Finally, we conclude such symbol has sense since negative heat is related with liberated heat.
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Answer:
b) velocity.
c) velocity, m/s²
d)change in velocity, change in direction, change in both velocity and direction.
e) increasing or decreasing
<span>Answer:
From the ideal gas law, MM=mRTPV; where MM = molecular mass; m = mass; P = pressure in atmospheres; V= volume in litres; R = gas constant with appropriate units.
So, 0.800â‹…gĂ—0.0821â‹…Lâ‹…atmâ‹…Kâ’1â‹…molâ’1Ă—373â‹…K0.256â‹…LĂ—0.987â‹…atm = 97.0 gâ‹…molâ’1.
nĂ—(12.01+1.01+2Ă—35.45)â‹…gâ‹…molâ’1 = 97.0â‹…gâ‹…molâ’1.
Clearly, n = 1. And molecular formula = C2H2Cl2.
I seem to recall (but can't be bothered to look up) that vinylidene chloride, H2C=C(Cl)2 is a low boiling point gas, whereas the 1,2 dichloro species is a volatile liquid. At any rate we have supplied the molecular formula as required.</span>
Answer:
equation number 3 is balanced.
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