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kati45 [8]
3 years ago
15

Write an expression to match the words three times the sum of 8and4

Mathematics
2 answers:
svet-max [94.6K]3 years ago
6 0
Easy, the equation should look like this:

3(8+4), your answer

3(12)

=36.
elena55 [62]3 years ago
3 0
Three times the sum of 8 and 4 is simply 3(8+4).
Solved, this should look like
3(8+4)
3(12)
36
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In the figure below what is the value of x?
vazorg [7]

Answer:

The value of x is 106

Step-by-step explanation:

Let us solve the question

In the given figure

∵ The triangle in the given figure has two sides equal

→ That means the triangle is an isosceles triangle

∴ The triangle is isosceles

∵ In the isosceles triangle, the base angles are equal in measures

∵ The measure of one base angle is 37°

∴ The measure of other base angle is 37°

→ The sum of the measures of the interior angles of a Δ is 180°

∵ 37° + 37° + x = 180°

→ Add the like terms

∴ 74° + x = 180°

→ Subtract 74 from both sides

∵ 74 - 74 + x = 180 - 74

∴ x = 106

∴ The value of x is 106

7 0
3 years ago
A pool has an area of 1,275 m2 and a width of 25 1/2 m. What is the length of the pool.
lisov135 [29]

Answer:

50m is the length of the pool

Step-by-step explanation:

area= length * width

length= area/ width

1275/ 25.5 = 50

5 0
3 years ago
Yen paid $10.50 for 2.5 pounds of pretzels. What price did she pay for each pound of pretzels? Move decimal O $0.42 0 $4.20 Divi
Grace [21]

Answer: The answer is $4.20

Step-by-step explanation:

6 0
3 years ago
HELP ASAP PLZZZZ
Tcecarenko [31]
QUESTION 1

The given system of equations is

3d - e = 7...eqn(1)
d + e = 5...eqn(2)

To solve by linear combination, we add equation (1) to equation (2) to get,

3d  + d= 7 + 5


4d = 12


We divide through by 4 to obtain,


d =  \frac{12}{4}


d = 3


We put d=3 into equation (2) to get,



3+ e = 5


e = 5 - 3


e = 2


\boxed {The \: solution \: is  \: (3, 2)}



QUESTION 2


The given system is

4x + y = 5 ...eqn(1)

3x + y = 3 ...eqn(2)


To solve by linear combination, we subtract equation (2) from equation (1) to eliminate y from the equation.

This will give us,

4x - 3x = 5 - 3



This implies that,

x = 2


Put x=3 into equation (1) to get,

4(2) + y = 5

8+ y = 5


y = 5 - 8



y =  - 3

The solution is

(2,-3)



QUESTION 3

We want to solve the system;


a – 2b = –2 ....eqn(1)


2a + 2b = 14...eqn(2)

by linear combination.


We need to add equation (1) to equation (2) to eliminate b.


This implies that,

2a + a = 14 +  - 2




Simplify,

3a = 12



Divide both sides by 3 to get,


a = 4
Put a=4 into equation (2) to obtain,



2(4) + 2b = 14


8 + 2b = 14
2b = 14 - 8


2b = 6


b = 3


The ordered pair in the form (a, b) is

(4,3)



QUESTION 4

The given system of equations is


11x + 4y = 18 ...eqn(1)

3x + 4y = 2 ...eqn(2)


We subtract equation (2) from equation (1) to get,


11x - 3x = 18 - 2


8x = 16


x = 2


Put x=2 into equation (2) to obtain,


3(2) + 4y = 2


This implies that,


6 + 4y = 2


4y = 2 - 6


4y =  - 4


y=-1

The correct answer is (2,-1).




QUESTION 5

The given system is ;

2d + e = 8...eqn1

d – e = 4...eqn2


We add the two equations to eliminate e.


This implies that,

2d + d = 8 + 4


3d = 12



We divide both sides by 3 to get,


d = 4


We put d=4 into equation (2) to get,

4 - e = 4

- e = 4 - 4



- e = 0



e = 0


The solution is

(4,0)
7 0
3 years ago
What is different between solving inequalities and absolute value inequalities?
Ivenika [448]

Answer:

The absolute number of a number a is written as

|a|

And represents the distance between a and 0 on a number line.

An absolute value equation is an equation that contains an absolute value expression. The equation

|x|=a

Has two solutions x = a and x = -a because both numbers are at the distance a from 0.

To solve an absolute value equation as

|x+7|=14

You begin by making it into two separate equations and then solving them separately.

x+7=14

x+7−7=14−7

x=7

or

x+7=−14

x+7−7=−14−7

x=−21

An absolute value equation has no solution if the absolute value expression equals a negative number since an absolute value can never be negative.

The inequality

|x|<2

Represents the distance between x and 0 that is less than 2

Whereas the inequality

|x|>2

Represents the distance between x and 0 that is greater than 2

You can write an absolute value inequality as a compound inequality.

−2<x<2

This holds true for all absolute value inequalities.

|ax+b|<c,wherec>0

=−c<ax+b<c

|ax+b|>c,wherec>0

=ax+b<−corax+b>c

You can replace > above with ≥ and < with ≤.

When solving an absolute value inequality it's necessary to first isolate the absolute value expression on one side of the inequality before solving the inequality.

Step-by-step explanation:

Hope this helps :)

5 0
3 years ago
Read 2 more answers
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